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Andrew [12]
3 years ago
11

Which species should have the shortest bond length?

Chemistry
1 answer:
aev [14]3 years ago
3 0

Answer:

The correct option is: A) N₂

Explanation:

The Bond length of a chemical bond is the length of a chemical bond formed between two given atoms.

<u>Bond length is inversely proportional to the bond order</u> of the chemical bond, which is the total number of bonds between two atoms. <u>Thus as the bond order increases, the bond length decreases.</u>

A) N₂: The nitrogen-nitrogen bond in dinitrogen is a triple bond (N≡N).

Thus the bond order = 3.

B) O₂: The oxygen-oxygen bond in dioxygen is a triple bond (O=O).

Thus the bond order = 2.

C) SO₂: Sulfur dioxide is a resonance stabilized molecule and its resonance hybrid shows that the sulfur-oxygen bond in sulfur dioxide is a partial double bond.

Thus the bond order = 1.5

D) SO₃: Sulfur trioxide is a resonance stabilized molecule and its resonance hybrid shows that the sulfur-oxygen bond in sulfur trioxide is a partial double bond.

Thus the bond order = 1.33

<u>Since the bond order of N₂ is the largest, therefore, the N-N bond length is the shortest.</u>

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he rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate c
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The question is incomplete, here is the complete question:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0 kJ/mol . If the rate constant of this reaction is 6.7 M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

<u>Answer:</u> The rate constant at 324°C is 61.29M^{-1}s^{-1}

<u>Explanation:</u>

To calculate rate constant at two different temperatures of the reaction, we use Arrhenius equation, which is:

\ln(\frac{K_{324^oC}}{K_{244^oC}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_{244^oC} = equilibrium constant at 244°C = 6.7M^{-1}s^{-1}

K_{324^oC} = equilibrium constant at 324°C = ?

E_a = Activation energy = 71.0 kJ/mol = 71000 J/mol   (Conversion factor:  1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = 244^oC=[273+244]K=517K

T_2 = final temperature = 324^oC=[273+324]K=597K

Putting values in above equation, we get:

\ln(\frac{K_{324^oC}}{6.7})=\frac{71000J}{8.314J/mol.K}[\frac{1}{517}-\frac{1}{597}]\\\\K_{324^oC}=61.29M^{-1}s^{-1}

Hence, the rate constant at 324°C is 61.29M^{-1}s^{-1}

8 0
3 years ago
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Answer:

answer A has four valence electrons

Explanation:

The outer shell has 4 electrons, which are considered the valence electrons

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Metal oxides are compounds composed of metal ions and oxide ions. Nonmetal oxides are compounds composed of nonmetal atoms and oxygen atoms. The main difference between metal oxides and non metal oxides is that metal oxides are basic compounds whereas nonmetal oxides are acidic compounds.

Explanation:

have a great day ahead

tC

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