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Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.
Elements form bonds to increase their stability. The main types of bonds are:
- Metallic bonds: they are formed between metals and the electrons are in a delocalized cloud.
- Ionic bonds: they are formed between metals (lose electrons) and nonmetals (gain electrons)
- Covalent bonds: they are formed between nonmetals, which share electrons.
Regarding the bonds in FesO₄:
- Fe is a metal and S a nonmetal, thus they will form ionic bonds.
- S and O are both nonmetals, thus they will form covalent bonds.
Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.
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Hello! The answer is D
A good note for these is when there are three elements, one being a singular element and another a compound and there’s a single switch, this could show a single-displacement
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I believe the statement above is true. The stronger the wind, the larger the particles it erodes<span>. The stronger the wind, the larger the particles that are carried away.
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The conversion of 2 - butanol to 2 - nitrobutane involves conversion of 2 butanol to 2 - bromobutane and subsequently to 2 - nitrobutane.
In order to convert 2 - butanol to 2 - nitrobutane, an SN2 reaction is first carried out in which 2 - butanol is converted to 2 - bromobutane. This reaction proceeds with inversion of configuration at the chiral carbon as expected.
This product is subsequently reacted with silver nitrite in ethanol to yield 2 - nitrobutane along side silver bromide. Some alkyl nitrite is also produced as a by product. The components of the mixture are separated by fractional distillation. The scheme of the reaction is shown in the image attached to this answer. This reaction is only applied to primary and secondary alkyl halides.
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Answer:
Rareness, the others describe what the gold is and its properties.
