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Vikki [24]
2 years ago
15

An ion of sulfur has a smaller atomic radius than a neutral atom of sulfur because it loses an electron when becoming an ion.

Chemistry
1 answer:
julia-pushkina [17]2 years ago
4 0
Answer is FALSE. Because sulfur has no tendency to loss an electron, since its electronic configuration is 16, it always want to gain 2 electron to form S^2-, following octet rule.

The answer would be yes if it can lose an electron(because when an atom loses an electron it form cation whose nuclear charge remain as same as neutral atom but number of electron decreases. As a result the nuclear charge has to act on a fewer number of electron and hence there will be more attraction between the nuclear charge and outermost electrons resulting in decrease in size) but it is not possible in case of sulfur.
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This reaction is an example of an oxymercuration reaction of the organic product 1−hexyne.

Oxymercuration is shown in three steps to the right. The nucleophilic double bond attacks the mercury ion, releasing an acetoxy group. The mercury ion's electron pair attacks carbon on the double bond, generating a positive-charged mercuronium ion. Mercury's dxz and 6s orbitals give electrons to the double bond's lowest unoccupied molecular orbitals.

In the second stage, the nucleophilic H₂O attacks the highly modified carbon, freeing its mercury-bonding electrons. Electrons neutralize mercury ions by collapsing. Water molecules have positive-charged oxygen.

In the third stage, the negatively charged acetoxy ion released in the first step attacks the hydrogen of the water group, generating the waste product HOAc. The two electrons in the oxygen-hydrogen link collapse into oxygen, neutralizing its charge and forming alcohol.

You can also learn about organic products from the following question:

brainly.com/question/13513481

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