Answer:
The answer to your question is 58.5 g of NaCl
Explanation:
Data
mass of NaCl = ?
mass of HCl = 40 g
mass of NaOH = 40 g
Balanced chemical reaction
HCl + NaOH ⇒ H₂O + NaCl
-Calculate the molar mass of the reactants
HCl = 1 + 35.5 = 36.5 g
NaOH = 23 + 16 + 1 = 40 g
-Calculate the limiting reactant
theoretical proportion = HCl/NaOH = 36.5 / 40 = 0.9125
experimental proportion = HCl / NaOH = 40 / 40 = 1
As the experimental proportion was higher than the theoretical proportion, the limiting reactant is NaOH.
-Calculate the molar mass of NaCl
NaCl = 23 + 35.5 = 58.5
-Calculate the experimental mass of NaCl
40 g of NaOH -------------------- 58.5 g of NaCl
40 g of NaOH ------------------- x
x = (40 x 58.5) / 40
x = 58.5 g of NaCl