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Mekhanik [1.2K]
3 years ago
14

If a battery-operated car has a resistance of 3 Ohms and the current moving through it is 2 amps, what is the voltage of the bat

tery?
A) 6V
B) 1.5 V
C) 1 V
D) 0.67 V
Physics
2 answers:
aivan3 [116]3 years ago
6 0

Answer:

A) 6V

Explanation:

To solve this problem we need to use ohm's law

We have the resistance

Resistance=R=3ohms

and the current:

Current=I=2A

To find the voltage we use the following formula from ohm's law:

Voltage=(Current)(Resistance)

so

V=I*R

substituting the known values:

V=(2A)(3ohms)=6volts

the voltage of the battery is 6V which is option A.

Leno4ka [110]3 years ago
5 0

Answer:

For me I think it is A

Explanation:

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Riders in a carnival ride stand with their backs against the wall of a circular room of diameter
Veseljchak [2.6K]

Answer:

option C

Explanation:

given,

diameter of circular room = 8 m

rotational velocity of the rider = 45 rev/min

                  = 45 \times \dfrac{2\pi}{60}

                  =4.712 rad/s

here in this case normal force is equal to centripetal force

N = m r ω²

N = m x 4 x 4.712²

N = 88.83m

frictional force = μ N

    = 88.83m x μ

now, for the body to not to slide

gravity force is equal to frictional force

m g = 88.83 m x μ

g = 88.83 x μ

9.8 = 88.83 x μ

 μ = 0.11

hence, the correct answer  is option C

6 0
3 years ago
Here is a graph of speed vs time. If the object is moving to the east, which BEST describes the speed and velocity of the graph?
Artemon [7]

Answer:

Both speed and velocity are changing.

Explanation:

They are both going up so both are changing

5 0
2 years ago
The diagram below shows the path of a planet around a star.
Anit [1.1K]

Answer:

Point C

Explanation:

Centripetal acceleration ac is inversely proportional to radius of orbit so it is greatest at point C.

7 0
2 years ago
6. A .25 kg arrow with a velocity of 12 m/s to the west strikes and pierces the center of a 6.8 kg target. a. What is the final
Alenkasestr [34]

Answer:

(a) the final velocity of the combined mass is 9.43 m/s

(b) the decrease in kinetic energy during the collision is 386.1 J

Explanation:

Given;

mass of arrow, m₁ = 25 kg

initial velocity of arrow, u₁ = 12 m/s

mass of target, m₂ = 6.8 kg

initial velocity of the target, u₂ = 0

Part (a)

From the principle of conservation of linear momentum;

Total momentum before collision = Total momentum after collision

m₁u₁ + m₂u₂ = v(m₁+m₂)

where;

v is the final velocity of the combined mass

25 x 12 + 0 = v(25 + 6.8)

300 = v(31.8)

v = 300/31.8

v = 9.43 m/s

Part(b)

Kinetic Energy, K.E = ¹/₂mv²

Initial kinetic energy =  ¹/₂m₁u₁² + ¹/₂m₂u₂²  = ¹/₂ x 25 x (12)² + 0 = 1800 J

Final kinetic energy = ¹/₂m₁v² + ¹/₂m₂v² = ¹/₂v²(m₁ + m₂)

                                                               = ¹/₂ x (9.43)²(25+6.8)

                                                               = 1413.91 J

Decrease in kinetic energy = Initial K.E - Final K.E

Decrease in kinetic energy = 1800J - 1413.91 J = 386.1 J

                               

4 0
3 years ago
in a thermal power plant, heat from the flue gases is recovered in (A) chimney (B) de-super heater (C) economizer (D) condenser
Volgvan

Answer:

(A)chimney

Explanation:

bc all the smoke is going into the chimney

8 0
3 years ago
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