2 years ago

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Chemistry

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hodyreva [135]2 years ago

4 0

Answer:

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Explanation:

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The chemistry teacher asked George to transfer an ideal gas from container A to container B. Container B is half the size of con

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What is the percentage of s-character in an sp hybrid? O 25% 50% o 75% O 66%

marishachu [46]

Answer: 50%

Explanation:

The number of electron pairs are 2 for hybridization to be $sp$ and the electronic geometry of the molecule will be linear.

1. percentage of s character in sp hybrid orbital = $\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{2}\times 100=50\%$

2. percentage of s character in $sp^2$ hybrid orbital = $\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{3}\times 100=33.3\%$

3. percentage of s character in $sp^3$ hybrid orbital = $\frac{\text {number of s orbitals}}{\text {total number of orbitals}}=\frac{1}{4}\times 100=25\%$

Thus percentage of s-character in an sp hybrid is 50%.

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2 years ago

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13.4 billion years is 3 times of the half-life, 4.47 billion years. So the Uranium-238 will go through three times of half decay. So the remain percentage will be 50%*50%*50%=12.5%.

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