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3 years ago

Which of the following statements about kinetic energy is NOT true?

Physics

1 answer:

maxonik [38]3 years ago

4 0

B the more kinetic energy an object's particles have the lower the objects temperature is

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Which best describes the differences between a resume and a CV?

son4ous [18]

Answer:

The resume will be tailored to each position whereas the CV will stay put and any changes will be in the cover letter. ... I would say the main difference between a resume and a CV is that a CV is intended to be a full record of your career history and a resume is a brief, targeted list of skills and achievements

Explanation:

8 0

3 years ago

To neutralize gastric juices in your stomach antacids contain

lara31 [8.8K]

To neutralize gastric juices in your stomach antacids contain basic chemicals. The acid in your stomach has a lower pH value. To neutralize this and reach a pH of 7, the antacid must contain a base.

3 0

3 years ago

Sheila weighs 60 kg and is riding a bike. Her momentum on the bike is 340 kg • m/s. The bike hits a rock, which stops it complet

Vikki [24]

Answer:

v₂ = 5.7 m/s

Explanation:

We will apply the law of conservation of momentum here:

$Total\ Initial\ Momentum = m_{1}v_{1} + m_{2}v_{2}\\$

where,

Total Initial Momentum = 340 kg.m/s

m₁ = mass of bike

v₁ = final speed of bike = 0 m/s

m₂ = mass of Sheila = 60 kg

v₂ = final speed of Sheila = ?

Therefore,

$340\ kg.m/s = m_{1}(0\ m/s) + (60\ kg)v_{2}\\v_{2} = \frac{340\ kg.m/s}{60\ kg}\\\\$

6 0

3 years ago

Glycerin is poured into an open U-shaped tube until the height in both sides is 20 cm. Ethyl alcohol is then poured into one arm

cestrela7 [59]

Answer:

0.043 m

Explanation:

From the attachment, the shaded part is the ethyl alcohol. The crossed part on the other hand, is that of glycerin.

The height of the Ethyl Alcohol is h2 = 0.25 m, it's density is ρ2 = 790 kg/m³. The density of glycerin is ρ1 = 1260 kg/m³

If we assume pressure at the two points to be the same, then

P1 = P2

ρ1.g.V1 = ρ2.g.V2

ρ1.A.h1 = ρ2.A.h2

ρ1.h1 = ρ2.h2, making h1 subject of formula

h1 = ρ2.h2 / ρ1, so that

h1 = 790 * 0.25 / 1260

h1 = 197.5 / 1260

h1 = 0.157 m

Δh = 0.2 - 0.157

Δh = 0.043 m or 4.3 cm

8 0

3 years ago

What force will a proton experience in a uniform electric field whose strength is 2.00 x 10^5 Newtons per Coulomb? *

Alenkasestr [34]

Answer: F =3.218 * 10^-11 N

Explanation: The relationship between electric field intensity and force is given by

F = Eq.

F= Force on electron

E = strength of electric field = 2*10^5

q= magnitude of proton charge = 1.609 * 10^-19c

F = 2* 10^5 * 1 609 * 10^-16

F = 3.218 * 10^-11 N

7 0

3 years ago