To answer the two questions, we need to know two important equations involving centripetal movement:
v = ωr (ω represents angular velocity <u>in radians</u>)
a = 
Let's apply the first equation to question a:
v = ωr
v = ((1800*2π) / 60) * 0.26
Wait. 2π? 0.26? 60? Let's break down why these numbers are written differently. In order to use the equation v = ωr, it is important that the units of ω is in radians. Since one revolution is equivalent to 2π radians, we can easily do the conversion from revolutions to radians by multiplying it by 2π. As for 0.26, note that the question asks for the units to be m/s. Since we need meters, we simply convert 26 cm, our radius, into meters. The revolutions is also given in revs/min, and we need to convert it into revs/sec so that we can get our final units correct. As a result, we divide the rate by 60 to convert minutes into seconds.
Back to the equation:
v = ((1800*2π)/60) * 0.26
v = (1800*2(3.14)/60) * 0.26
v = (11304/60) * 0.26
v = 188.4 * 0.26
v = 48.984
v = 49 (m/s)
Now that we know the linear velocity, we can find the centripetal acceleration:
a = 
a = 
a = 9234.6 (m/
)
Wow! That's fast!
<u>We now have our answers for a and b:</u>
a. 49 (m/s)
b. 9.2 *
(m/
)
If you have any questions on how I got to these answers, just ask!
- breezyツ
2^4/2^7 = 16/128 = 0.125
(1/2)^3= 0.125
1/8= 0.125
a and f are equivalent
It would be static friction which is what you have to overcome when an object is not in motion. When you move an object friction works against it like gravity and air resistance. I hope this helps!
Answer:
The escape velocity on the planet is approximately 178.976 km/s
Explanation:
The escape velocity for Earth is therefore given as follows
The formula for escape velocity,
, for the planet is 
Where;
= The escape velocity on the planet
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
m = The mass of the planet = 12 × The mass of Earth, 
r = The radius of the planet = 3 × The radius of Earth, 
The escape velocity for Earth,
, is therefore given as follows;


= 16 ×
Given that the escape velocity for Earth,
≈ 11,186 m/s, we have;
The escape velocity on the planet =
≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.