21. What are the two main ways of working with clay?
2 answers:
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Answer:
The temperature at which the liquid vapor pressure will be 0.2 atm = 167.22 °C
Explanation:
Here we make use of the Clausius-Clapeyron equation;
Where:
P₁ = 1 atm =The substance vapor pressure at temperature T₁ = 282°C = 555.15 K
P₂ = 0.2 atm = The substance vapor pressure at temperature T₂
= The heat of vaporization = 28.5 kJ/mol
R = The universal gas constant = 8.314 J/K·mol
Plugging in the above values in the Clausius-Clapeyron equation, we have;
T₂ = 440.37 K
To convert to Celsius degree temperature, we subtract 273.15 as follows
T₂ in °C = 440.37 - 273.15 = 167.22 °C
Therefore, the temperature at which the liquid vapor pressure will be 0.2 atm = 167.22 °C.
Jasmine pushes an object a distance of 15 m at constant speed. It produces a 450J of work on the object. What strength Jasmine does it exert on the object?
Answer:
30J
Explanation:
Given parameters:
Distance moved = 15m
Work done = 450J
Unknown:
Strength Jasmine applied = ?
Solution:
The strength Jasmine applied or exerted on the object is the force of pull that cause the motion of the object and the distance it was moved.
Now;
Work done = Force x distance
So;
450 = Force x 15
Force = = 30J