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Gennadij [26K]
3 years ago
6

21. What are the two main ways of working with clay?

Chemistry
2 answers:
Ludmilka [50]3 years ago
5 0

Answer:

Diferentes tipos de arcilla

ARCILLA DE LADRILLOS. Contiene muchas impurezas. ...

ARCILLA DE ALFARERO. Llamada también barro rojo y utilizada en alfarería y para modelar. ...

ARCILLA DE GRES. Es una arcilla con gran contenido de feldespato. ...

ARCILLAS “BALL CLAY” O DE BOLA. ...

CAOLIN. ...

ARCILLA REFRACTARIA. ...

BENTONITA.

Explanation:

pishuonlain [190]3 years ago
3 0

Answer:

Coil method and the slab method.

Explanation:

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A eraser has a mass of 4g and a volume of 2cm3 what is it’s density
sladkih [1.3K]

Answer:

<h3>The answer is 2.0 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 4 g

volume = 2 cm³

We have

density =  \frac{4}{2}  \\

We have the final answer as

<h3>2.0 g/cm³</h3>

Hope this helps you

4 0
3 years ago
The point on a phase diagram at which all phases occur simultaneously is called the: -end point
Assoli18 [71]

Answer:The boiling point

Explanation:

6 0
3 years ago
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400 ms^2/0.080 s <br><br> solve
Nana76 [90]

Answer: 5000ms^2 s

Explanation:

5 0
3 years ago
What is hydrolysis?​
harkovskaia [24]

Answer:

Hydrolysis is any chemical reaction in which a molecule of water ruptures one or more chemical bonds.

Explanation:

Example:

Dissolving a salt of a weak acid or base in water is an example of a hydrolysis.

8 0
4 years ago
Read 2 more answers
Calculate the volume of a 2.30 mol/L solution of Na2CO3 that contains 0.325 mol of solute.
Blababa [14]

Answer:

141 mL is the volume of a 2.30 mol/L solution of Na₂CO₃ that contains 0.325 mol of solute.

Explanation:

Molarity is a measure of concentration of a solution that indicates the amount of moles of solute that appear dissolved in each liter of the mixture.

So 2.30 mol / L indicates that 2.30 moles dissolve in 1 L of solution. You want to know in what volume is contained 0.325 mol of solute. For this you apply the following rule of three: if 2.30 moles of solute are present in 1 L of solution, 0.325 moles in how much volume is it?

volume=\frac{0.325 moles*1L}{2.30 moles}

volume= 0.141 L

Being 1L=1000 mL, then 0.141 L=141 mL

<u><em>141 mL is the volume of a 2.30 mol/L solution of Na₂CO₃ that contains 0.325 mol of solute.</em></u>

5 0
3 years ago
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