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zhuklara [117]
3 years ago
7

if the coolant in a refrigerator was not compressed back into a liquid after it flowed through the refrigerator what would happe

n

Physics
2 answers:
Olin [163]3 years ago
4 0

The system would stop cooling, and simply recycle warm vapor through the refrigeration loop.

Explanation:

From the Mollier diagram we see that one part of the “refrigeration” loop is not complete. The step from 1 to 2 in the diagram would not occur.
This may occur due to a lack of sufficient refrigerant in the system or a faulty compressor. In any case, this results in warm “coolant” vapor passing into the receiver without any condensation (Step 3-4 cannot happen).
Without any liquid coolant available, the cooling effect of expansion of the liquid through the evaporator is lost (step from 5-6), and the system will simply use energy (and generate more heat) while recirculating warm vapor.

Pavlova-9 [17]3 years ago
3 0

Less heat would be removed from the refrigerator.

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Find the ratio of the lengths of the two mathematical pendulums, if the ratio of periods is 1.5​
juin [17]

Answer:

The ratio of lengths of the two mathematical pendulums is 9:4.

Explanation:

It is given that,

The ratio of periods of two pendulums is 1.5

Let the lengths be L₁ and L₂.

The time period of a simple pendulum is given by :

T=2\pi \sqrt{\dfrac{l}{g}}

or

T^2=4\pi^2\dfrac{l}{g}\\\\l=\dfrac{T^2g}{4\pi^2}

Where

l is length of the pendulum

l\propto T^2

or

\dfrac{l_1}{l_2}=(\dfrac{T_1}{T_2})^2 ....(1)

ATQ,

\dfrac{T_1}{T_2}=1.5

Put in equation (1)

\dfrac{l_1}{l_2}=(1.5)^2\\\\=\dfrac{9}{4}

So, the ratio of lengths of the two mathematical pendulums is 9:4.

3 0
3 years ago
A load of 250 kg is hung by a crane's cable. The load is pulled by a horizontal force such that the cable makes a 30 angle to th
Anna [14]

Answer:

1250\sqrt{3}

Explanation:

Let's look at this in a simple manner, because it is.

The crane weights 250Kg. Okay.

Since it is hung, there is the acceleration of gravity being applied on it (10m/s²)

Since F = m * a

F = 250 * 10

F = 2500

Now we know that the downward Force is 2500N.

To find the force that is being applied on that 30° angle, we can multiply our 2500N by cos30°, which happens to be \frac{\sqrt{3}}{2}.

Therefore, the force pulling the box in the cable's direction is:

\frac{2500\sqrt{3} }{2}  = 1250\sqrt{3}

<em />

<em>If you have any questions feel free to comment.</em>

<em />

<em>Have a great one and mark brainliest if it helped, please</em>

8 0
2 years ago
A playground carousel is rotating counterclockwise about its center on frictionless bearings. A person standing still on the gro
Shtirlitz [24]

Answer:

1.94601 rad/s

Explanation:

I_1 = Moment of inertia of carousel = 124 kgm²

\omega_1 = Angular speed of carousel = 3.5 rad/s

\omega_2 = Angular speed of person

r = Radius of carousel = 1.53 m

m = Mass of person = 42.3 kg

Moment of inertia of person

I_2=mr^2\\\Rightarrow I_2=42.3\times 1.53^2\\\Rightarrow I_2=99.02007\ kgm^2

As the angular momentum is conserved in the system

I_1\omega_1=(I_1+I_2)\omega_2\\\Rightarrow \omega=\frac{I_1\omega_1}{(I_1+I_2)}\\\Rightarrow \omega_2=\frac{124\times 3.5}{(124+99.02007)}\\\Rightarrow \omega_2=1.94601\ rad/s

The angular speed of the carousel after the person climbs aboard is 1.94601 rad/s

5 0
3 years ago
A rising pendulum bob gains _____ energy.
puteri [66]

Answer:

B. Kinetic energy.............

4 0
3 years ago
Read 2 more answers
What is the average speed of a car that travels 60 meters in 2<br> seconds?
blondinia [14]

Answer:

30 m/s

Explanation:

Speed is distance over time. 60 meters / 2 seconds, = 30 m/s.

6 0
3 years ago
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