Answer:
0.71121 km/s
Explanation:
= Velocity of planet initially = 54 km/s
= Distance from star = 0.54 AU
= Final velocity of planet
= Final distance from star = 41 AU
As the angular momentum of the system is conserved

When the exoplanet is at its farthest distance from the star the speed is 0.71121 km/s.
Answer:
Because on different surfaces there's more/less friction. Smooth surfaces will allow the duster to accelerate while rough surfaces will decrease the acceleration.
Answer:
(a): The normal force on the car from the track when the car's speed is v= 7.6 m/s is FN= -6696 N.
(b): The normal force on the car from the track when the car's speed is v= 17 m/s is FN= 8912.7 N.
Explanation:
m= 1080 kg
r= 16m
v1= 7.6 m/s
v2= 17 m/s
g= 9.81 m/s²
v1= w1*r
w1= v1/r
w1= 0.475 rad/s
ac1= w1² * r
ac1= 3.61 m/s²
FN= m * (ac1 - g)
FN= -6696 N (a)
-----------------------------------------------------
v2= w2*r
w2= v2/r
w2= 1.06 rad/s
ac2= w2² * r
ac2= 18.06 m/s²
FN= m * (ac2 - g)
FN= 8912.7 N (b)
Answer:

Explanation:
<u>Displacement</u>
It is a vector that points to the final point where an object traveled from its starting point. If the object traveled to several points, then the individual displacements must be added as vectors.
The mail carrier leaves the post office and drives 2 km due north. The first displacement vector is

Then the carrier drives 7 km in 60° south of east. The displacement has two components in the x and y axis given by

Finally, he drives 9.5 km 35° north of east.

The total displacement is


The direction can be calculated with

