Answer:
1.0 *10^(-4) mol
Explanation:
For gases:
n1/n2 = V1/V2
n1/3.8*10^(-4) mol = 230 mL/ 860 mL
n1 = 3.8*10^(-4)*230/860 = 1.0 *10^(-4) mol
Answer : The molar heat of solution of KCl is, 17.19 kJ/mol
Explanation :
First we have to calculate the heat of solution.

where,
q = heat produced = ?
c = specific heat capacity of water = 
= change in temperature = 0.360 K
Now put all the given values in the above formula, we get:


Now we have to calculate the molar heat solution of KCl.

where,
= enthalpy change = ?
q = heat released = 460.8 J
m = mass of
= 2.00 g
Molar mass of
= 74.55 g/mol

Now put all the given values in the above formula, we get:


Therefore, the molar heat of solution of KCl is, 17.19 kJ/mol
There are two molecular orbitals in the CH2O or formaldehyde. These are designated by the two types of bonding involved. The first is the sigma bonding. It is the head-on overlap of electrons of the C and H atoms. The second molecular orbital is formed from the pi orbital bonding. This is a sideway overlap of electrons between C-O bonding.
Answer:
False
Explanation:
Not all of it but some of it. Hope this helps! (ノ◕ヮ◕)ノ*:・゚✧