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AysviL [449]
3 years ago
14

A wheel of mass 48 kg is lifted to a height of 0.8 m. How much gravitational potential energy is added to the wheel? Acceleratio

n Due to gravity is g = 9.8 m/s2.
A. 30.4 J
B. 3.1 J
C. 297.9 J
D. 11,321 J
Physics
1 answer:
ANTONII [103]3 years ago
5 0

Answer: 376.32 J

Explanation: Gravitational potential energy is the energy possessed by a body by virtue of its position.

P.E=mgh

m= mass of the body = 48 kg

g= acceleration due to gravity= ]9.8m/s^2

h= height of body= 0.8 m

P.E=48kg\times 9.8m/s^2\times 0.8m=376.3J (1kgm^2s^{-2}=1 J)

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Light of wavelength 476.1 nm falls on two slits spaced 0.29 mm apart. What is the required distance from the slits to the screen
stich3 [128]

Answer:

The distance is D  =  2.6 \ m

Explanation:

From the question we are told that

    The wavelength of the light is  \lambda  =  476.1 \ nm  =  476.1 *10^{-9} \ m

      The  distance between the slit is  d =  0.29 \  mm  =  0.29 *10^{-3} \ m

       The  between the first and second dark fringes is  y =  4.2 \ mm  =  4.2 *10^{-3} \ m

Generally  fringe width is mathematically represented as

       y  =  \frac{\lambda * D }{d}

Where D is the distance of the slit to the screen

   Hence

        D  =  \frac{y *  d}{\lambda }

substituting values

       D  =  \frac{ 4.2 *10^{-3} *   0.29 *10^{-3}}{ 476.1 *10^{-9} }

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7 0
3 years ago
Two wheels with fixed hubs and radii 0.51 m and 1.9 m, each having a mass of 3 kg, start from rest. Forces 5 N and F2 are applie
Katarina [22]

Answer:

18.63 N

Explanation:

Assuming that the sum of torques are equal

Στ = Iα

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On making α subject of formula, we have

α = 2.55 / 0.7803

α = 3.27

If we make the α of each one equal to each other so that

5 / (3 * 0.51) = F2 / (3 * 1.9)

solve for F2 by making F2 the subject of the formula, we have

F2 = (3 * 1.9 * 5) / (3 * 0.51)

F2 = 28.5 / 1.53

F2 = 18.63 N

Therefore, the force F2 has to 18.63 N in order to impart the same angular acceleration to each wheel.

3 0
3 years ago
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