Answer:
48 seconds
Explanation:
Since S=d/t, plug in the known values and solve
0.25m/s=12m/t
0.25m/s*t=12m
t=12m/0.25m/s
t=48 seconds
Answer:
=1419.19 meters.
Explanation:
The time it takes for the shell to drop to the tanker from the height, H =1/2gt²
610m=1/2×9.8×t²
t²=(610m×2)/9.8m/s²
t²=124.49s²
t=11.16 s
Therefore, it takes 11.16 seconds for a free fall from a height of 610m
Range= Initial velocity×time taken to hit the tanker.
R=v₁t
Lets change 300 mph to kph.
=300×1.60934 =482.802 kph
Relative velocity=482.802 kph-25 kph
=457.802 kph
Lets change 11.16 seconds to hours.
=11.16/(3600)
=0.0031 hours.
R=v₁t
=457.802 kph × 0.0031 hours.
=1.41918 km
=1.41919 km × 1000m/km
=1419.19 meters.
I think b but I’m not completely sure
Answer:
decantation, distilling, freezing
The JWST is postioned about 1.5 million kilometers from the earth on the side facing away from the sun