The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
B is correct because is the force was large then the nail would bend itself
<em>The question is incomplete and doesn't have any requirement. I'm computing the angle at which the dart should have been thrown to hit in the center of the target</em>
Answer:
The dart should be thown with an angle of elevation of
Explanation:
<u>Horizontal and Diagonal Motion</u>
When an object is launched horizontally, its initial vertical speed is zero and the horizontal component remains the same in time. If the initial velocity forms an angle with the horizontal, then the vertical velocity has an initial value which can be positive or negative depending on the angle (above or below the horizontal).
The dart is thrown horizontally and when it reaches the target, 5 meters away, the center of the target was missed by 0.15 meters below. The question doesn't have any requirement, but I'll assume you want to know at what angle should the dart be thrown at the same speed, to be exact on target.
Let's start with the original horizontal launching. The distance x is computed as
The distance y is
We need to find the value of , given x and y. Solving for t in the last equation
Replacing in x
Solving for
Now, let's suppose we try to reach the center of the target by throwing the dart at the same speed but with a certain angle above the horizontal. That way, the formulas for x changes to
Replacing the value of
Operating
Simplifying
Solving for the angle
The loop is in the vertical plane and normal to the north direction. The current in the loop can be calculated with the equation : I=2BR,
where B is the direction (B=0.7G) and R is the radius,
So,
I=2*7*10^(-5) x 0.1/4pi*1-^(-7) Ampers