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Explanation:
Answer:
W ≅ 292.97 J
Explanation:
1)What is the work done by tension before the block goes up the incline? (On the horizontal surface.)
Workdone by the tension before the block goes up the incline on the horizontal surface can be calculated using the expression;
W = (Fcosθ)d
Given that:
Tension of the force = 62 N
angle of incline θ = 34°
distance d =5.7 m.
Then;
W = 62 × cos(34) × 5.7
W = 353.4 cos(34)
W = 353.4 × 0.8290
W = 292.9686 J
W ≅ 292.97 J
Hence, the work done by tension before the block goes up the incline = 292.97 J
<h2>The voltmeter reading will be 35.7 volt </h2>
Explanation:
The resistor 1000 ohm and 4000 ohm are connected in parallel .
Their combined resistance is supposed R₁
Thus
=
+
or R₁ = 800 ohm
Therefore the total resistance in circuit is = 2000 + 800 = 2800 ohm
Because these are in series .
We can find current flowing through the circuit I =
=
= 
here R is total resistance .
The potential difference across 1000 ohm =
x 1000 = 35.7 volt
Thus voltmeter reading will be 35.7 volt
Answer:
90 J
Explanation:
W=fd
W=(75)(1.2)
W= 90 J
Answer:
Explanation:
To calculate the time it took the car to hit the ground, we use the formula
speed = distance/time
80 m/s = 300 m/time
time = 300/80
time = 3.75 secs
It must have taken the car 3.75 seconds to hit the ground
To determine the horizontal distance of the car before hitting the ground, the same formula will also be used but with the time obtained above (since that was the time it took before hitting the ground)
speed = distance/time
80 = distance/3.75
distance = 3.75 x 80
distance = 300 meters