Answer:
a) The US power rating for the european bulb must be 27.27 W
b) The current in the United Stated for the european bulb is 0.227A
Explanation:
First of all the bulb is not going to light in 120V like it does in 220V, the bright is going to be much lower (near 1/4). Now, lets take a look on a circuit perspective:
The bulb in a circuit is modeled like a simple resistor, so we have a resistor conected to a voltage source, see figure 1. There we have a current
given by:

Where
is the 220v Input voltage, R is the resistance from the bulb. In the problem we have the power consumption in watts given by:
![W_{1}= V_{1]*I_{1}](https://tex.z-dn.net/?f=W_%7B1%7D%3D%20V_%7B1%5D%2AI_%7B1%7D)
Clearing

Now, from ohm's law

So 484 ohm is the resistance from the bulb.
Now in the circuit lets replace the voltage source from 220v to 120v and lets calculate the current, and the power consuptiom

And the power consuptiom:
![W_{2}= V_{2]*I_{2}=110*0.227=27.27Watts](https://tex.z-dn.net/?f=W_%7B2%7D%3D%20V_%7B2%5D%2AI_%7B2%7D%3D110%2A0.227%3D27.27Watts)
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<em><u>Additional</u></em><em><u> </u></em><em><u>information</u></em><em><u>:</u></em>
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Answer:
n = 1.56
Explanation:
The total reflection attempts occurs when a light beam passes from a medium with a higher index to a medium with a lower nest, at an angle where it occurs we can find them by the refractive relationship
n₁ sin θ₁ = n₂ sin θ₂
n1 = n2 / sin θ₁
For this relationship to be fulfilled, the liquid index must be greater than the air index divided by the sine of the critical angle
Let's use trigonometry to find angle
tan θ = y / x
θ = tan⁻¹ 7.2 / 8.6
θ = 39.94º
n₁ = 1 / sin 39.94
n = 1.56
This is the refractive index of the liquid
Answer:
Alpha = ω^2 R where R is radius of blade
g = w^2 r where r is distance from center
ω^2 R = 11.5 ω^2 r
R / r = 11.5 / 9.8 = 1.17
Or r = .852 R
Since the angular acceleration depends on both R and ω it seems that one can only get r as it depends on R