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Leni [432]
2 years ago
13

Complete the passage to differentiate between longitudinal and transverse waves.

Physics
2 answers:
koban [17]2 years ago
8 0

Answer:

parallel, and perpendicular

Explanation:

astra-53 [7]2 years ago
3 0

Complete sentence:

A longitudinal wave is a type of wave that transfers energy parallel to the direction of wave motion. A transverse wave, on the other hand, is a type of wave that transfers energy perpendicular to the direction of wave motion.

Explanation

the main difference between longitudinal and transverse wave is the direction of their oscillation/vibration. In a longitudinal wave, the oscillation of the wave occurs in a direction parallel to the direction of propagation of the wave, while in a transverse wave, the oscillation occurs in a plane perpendicular to the direction of propagation. An example of transverse waves are the electromagnetic waves, which consists of an electric field and a magnetic field that oscillates perpendicular to the direction of the wave, while an example of longitudinal waves are the sound waves, whose particles vibrate in a direction parallel to the direction of motion of the wave, producing regions of more density of particles (called compressions) and regions of less density of particles (called rarefactions).

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In Example 2.12, two circus performers rehearse a trick in which a ball and a dart collide. Horatio stands on a platform 6.4 m a
pickupchik [31]

Answer:

time of collision is

t = 0.395 s

h = 5.63 m

so they will collide at height of 5.63 m from ground

Explanation:

initial speed of the ball when it is dropped down is

v_1 = 0

similarly initial speed of the object which is projected by spring is given as

v_2 = 16.2 m/s

now relative velocity of object with respect to ball

v_r = 16.2 m/s

now since we know that both are moving under gravity so their relative acceleration is ZERO and the relative distance between them is 6.4 m

d = v_r t

6.4 = 16.2 t

t = 0.395 m

Now the height attained by the object in the same time is given as

h = v_2 t - \frac{1}{2}gt^2

h = 16.2(0.395) - \frac{1}{2}(9.81).395^2

h = 5.63 m

so they will collide at height of 5.63 m from ground

4 0
3 years ago
If a cup of coffee is at 90°C and a person with a body temperature of 36°C touches it, how will heat flow between them?
Alex73 [517]
B: from the cup to the hand. 
3 0
3 years ago
Read 2 more answers
Each of the space shuttle's main engines is fed liquid hydrogen bya high-pressure pump. Turbine blades inside the pump rotateat
kvasek [131]

Answer:

a) a= \frac{4 \pi^2 (0.02 m)^2}{0.00162 s}=9.74 \frac{m}{s^2}

b) k = \frac{9.8}{9.74}=1.006

Explanation:

Part a

For this case we can begin finding the period like this:

T= \frac{1}{w} =\frac{1}{617 rad/s}=0.00162 s

Then we know that the centripetal acceleration is given by:

a= \frac{v^2}{r}

And the velocity is given by:

v=\frac{2\pi r}{T}

If we replace this into the acceleration we got:

a = \frac{(\frac{2\pi r}{T})^2}{r}= \frac{4 \pi^2 r}{T^2}

And we can replace the values and we got:

a= \frac{4 \pi^2 (0.02 m)^2}{0.00162 s}=9.74 \frac{m}{s^2}

Part b

For this case we want to find a value of k such that:

a= k 9.8

Where a = 9.74, so then we can solve for k like this:

k = \frac{9.8}{9.74}=1.006

8 0
3 years ago
Define moment of momentum. at which condition is it's magnitude zero?​
ololo11 [35]

Let's start with the concept of momentum. What is it? Linear momentum in physics is mathematically written as a product of mass and velocity of an object. Now let us suppose a body of mass m is moving in an inertial frame of reference with velocity v. Consider the fact that no external force is acting on the system. The momentum of this body is given by mv, where m is the mass and v is its velocity. In case of simple real world problems not delving into the realms of relativity, mass is a conserved quantity and it cannot be zero. Hence the velocity of the body must be zero and hence the momentum.

However, photons are considered to have a rest mass zero.

However note the point carefully "rest mass". A body in motion cannot have mass to be zero.

<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em><em> ❤️</em>

7 0
2 years ago
The kinetic energy of a proton and that of an a-particle are 4 eV and 1 eV,
madam [21]

Answer:

  • <u><em>(b) 1:1</em></u>

Explanation:

<u></u>

<u>1. Formulae:</u>

  • E = hf  
  • E = h.v/λ
  • λ = h/(mv)
  • E = (1/2)mv²

Where:

  • E = kinetic energy of the particle
  • λ = de-Broglie wavelength
  • m = mass of the particle
  • v = speed of the particle
  • h = Planck constant

<u><em>2. Reasoning</em></u>

An alha particle contains 2 neutrons and 2 protons, thus its mass number is 4.

A proton has mass number 1.

Thus, the relative masses of an alpha particle and a proton are:

       \dfrac{m_\alpha}{m_p}=4

For the kinetic energies you find:

          \dfrac{E_\alpha}{E_p}=\dfrac{m_\alpha \times v_\alpha^2}{m_p\times v_p^2}

            \dfrac{1eV}{4eV}=\dfrac{4\times v_\alpha^2}{1\times v_p^2}\\\\\\\dfrac{v_p^2}{v_\alpha^2}=16\\\\\\\dfrac{v_p}{v_\alpha}=4

Thus:

           \dfrac{m_\alpha}{m_p}=4=\dfrac{v_p}{v__\alpha}

          m_\alpha v_\alpha=m_pv_p

From de-Broglie equation, λ = h/(mv)  

       \dfrac{\lambda_p}{\lambda_\alpha}=\dfrac{m_\lambda v_\lambda}{m_pv_p}=\dfrac{1}{1}=1:1

5 0
3 years ago
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