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Wewaii [24]
3 years ago
6

Is NaBr+I2 -> NaI+Br2 a single replacement

Chemistry
1 answer:
snow_lady [41]3 years ago
3 0

Is not a single replacement

<h3>Further explanation</h3>

A single replacement reaction is a chemical reaction in which one element replaces the other elements of a compound to produce new elements and compounds

Reactions

A+BC--> AC+B

Metal halogens can force metal halide ions in the order F> Cl> Br> I

Oxidation : F₂> Cl₂> Br₂> I₂

Reaction

NaBr+I₂ -> NaI+Br₂

Then the reaction will not occur because I₂ cannot oxidize Br, or the reaction is said to be non-spontaneous

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From the list of the instructions and tips below, select the statement that would NOT lead to a successful recrystallization O D
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C. Precipitate the crystals as fast as possible

Explanation:

C. Precipitate the crystals as fast as possible

Precipitation if done fast , can lead to the formation of impure crystals , as impurities also get stuck inside the crystals. So it must be done slowly to obtain the pure crystals . Slower the crystals form , purer they are .

All the other options can lead to a successful recrystallization.  

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The reation between sulfur dioxide and oxygen is a dynamic equilibrium. what happens when the pressure of the system is
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Draw the Lewis structure for SO32−, including lone pairs. Select Draw Rings More Erase Select Draw Rings More Erase Select Draw
balandron [24]

Answer :  The molecular shape of SO_3^{2-}  is trigonal pyramidal and bond angle between O-S-O is

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, SO_3^{2-}

As we know that sulfur has '6' valence electrons and oxygen also has '6' valence electron.

Therefore, the total number of valence electrons in SO_3^{2-} = 6 + 3(6) + 2 = 26

According to Lewis-dot structure, there are 8 number of bonding electrons and 18 number of non-bonding electrons or lone pair electrons.

The Lewis-dot structure of SO_3^{2-} is shown below.

Formula used  :

\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

Now we have to determine the hybridization of the given molecule, SO_3^{2-}

\text{Number of electrons}=\frac{1}{2}\times [6+2]=4

The number of electron pair are 4 that means the hybridization will be sp^3 and the electronic geometry of the molecule will be tetrahedral.

But as there are 3 atoms around the central sulfur atom, the fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be trigonal pyramidal and the bond angle between O-S-O is less than 109.5^o due to repulsion between lone and bond pair of electrons.

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