Compute the components of the given vectors. Let
denote the plane's velocity vector, and
the wind. Then



The resultant velocity (rounded) is

with magnitude
and direction
, or about 258 mi/hr at 47.7 degrees south of east.
Speed of the tip of the minute hand=V=0.0244 cm/s
Explanation:
The angular velocity of the minute hand is given by

T= time period of the minute hand=60 min=3600 s
so ω= 2 π/3600 rad/s
Now linear velocity v= r ω
r= radius of minute hand=14 cm
so v= 14 (2 π/3600)
V=0.0244 cm/s
Answer:
Explanation:
20.05 √Tk = 20.05 √355.8 = 378.196... ≈ 378 m/s
Thermal Expansion. best describes the increase in a materials volume
Answer:
a = 3,0 m/s²
Explanation:
En este ejercicio se pide calcular la aceleracion del cuerpo, usemos las ecuaciones de cinematica en una dimensión.
v= v₀ + a t
como el corredor parte del reposo si velocidad inicial es cero
v = at
a = v/t
calculemos
a = 12 /4,0
a = 3,0 m/s²