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san4es73 [151]
3 years ago
6

ASAP PLZ HELP!!

Mathematics
2 answers:
Dominik [7]3 years ago
4 0

Answer:

A) y² - 5y + 1

B) y² - 5y - 4

C) - 5y + 1

D) - 3y² - 4y - 6

Step-by-step explanation:

Let's call P the unkown polynomial and D the difference. In each case, the following must be true:

y² - 5y + 1 - P = D

<em>A)</em>

y² - 5y + 1 - P = 0

y² - 5y + 1 = P

<em>B)</em>

y² - 5y + 1 - P = 5

y² - 5y + 1 - 5 = P

y² - 5y - 4 = P

<em>C)</em>

y² - 5y + 1 - P = y²

y² - 5y + 1 - y² = P

- 5y + 1 = P

<em>D) </em>

y² - 5y + 1 - P = 4y² - y + 7

y² - 5y + 1 - 4y² + y - 7 = P

- 3y² - 4y - 6 = P

Mekhanik [1.2K]3 years ago
3 0

Answer:

Subtract each term from the polynomial until you find the matching polynomial.

Step-by-step explanation:

Subtracting each answer option below yields the following polynomials:

A) y^2-5y+1-0= y^2-5y+1

B) y^2-5y+1-5 = y^2-5y-4

C) y^2-5y+1-y^2 = -5y+1

D) y^2-5y+1 - (4y^2-y+7) \\y^2 -5y+1-4y^2+y-7\\-3y^2-4y-6

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Transitive Property AB=CD and CD = 10, then AB =?
gulaghasi [49]

Answer:

10

Step-by-step explanation:

AB = CD = 10, so AB = 10

3 0
3 years ago
Does anyone know how to answer this question? Please write your working calculation as well if you do know the answer. Thanks so
krek1111 [17]

Answer:

Mark as brainliest if helped Thanks!

Step-by-step explanation:

funtion is:

y = \frac{x^2 -1}{2x + 1}

therefore \\\frac{dy}{dx}\\ is

\frac{d\frac{x^2 -1}{2x + 1}}{dx}

\frac{\frac{x^2 -1}{2x + 1}}{x}

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Now

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(Calculation of this it too long and it is hard to type on brainly)

here is the answer though....

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5 0
3 years ago
Use the common denominator to find -2/3 + -4/5​
Svetlanka [38]

Answer:

-22/15

Step-by-step explanation:

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5 0
3 years ago
What is the estimate of 1/8+1/4
kotegsom [21]
3/8
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7 0
3 years ago
Read 2 more answers
If ∠CEF is complementary to ∠DCF, then ∠DCF ≅ ∠FEG.
scZoUnD [109]

Answer:

Correct answer is <em>A) Complements of the same angle are congruent.</em>

Step-by-step explanation:

According to Congruent Complement Theorem,

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Here, ∠CEF is complementary to ∠DCF, hence ∠DCF ≅ ∠FEG.

4 0
3 years ago
Read 2 more answers
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