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Nina [5.8K]
3 years ago
6

Two people stand across from one another at the top edges of identical buildings, 50 meters above the ground. One person throws

a rock straight upwards with an initial speed of 15 m/s, while the other person throws their rock straight downwards with an initial speed of 15 m/s. If both of the rocks miss the building and continue down to the street,
a. How long will it take for the rock thrown upwards to reach the ground?
b. How long will it take for the rock thrown downwards to reach the ground?
c. How fast will the upward thrown rock be travelling just before it hits the ground? The downward thrown rock?
Physics
1 answer:
cricket20 [7]3 years ago
6 0

Answer:

C

Explanation:

Hope this helps!!!!

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The plates on a capacitor have a radius of 1.5 mm and are separated by a distance of 0.43 mm. The space between the plates is fi
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So, C = kE°A/d

putting the values,

C
= 3.8 × 8.85×10^(-12) × 3.14×1.5×1.5 × 10^(-6)/0.43 × 10^(-3)

so, 1.02 × 10^(-13)

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1.4 × 10^(-13) ....answer !!
3 0
3 years ago
A myopic (nearsighted) lawyer has a far point of 60.0 cm. What is the diopter value of suitable corrective contacts?
Vlada [557]

Answer:

P = -1.67 dP

Explanation:

given,

myopic lawyer has a far point of = 60.0 cm = 0.6 m

If a person is suffering from myopia then he cannot see the farthest object clearly.

Image of far object does not form on the retina so, the image appear to be blur.

using lens formula

      \dfrac{1}{v}-\dfrac{1}{u} = \dfrac{1}{f}

                -\dfrac{1}{0.6} = \dfrac{1}{f}

                     \dfrac{1}{f} =P

                              P = -\dfrac{1}{0.6}

                              P = -1.67 dP

6 0
2 years ago
An iron block of mass 10 kg rests on a wooden plane inclined at 30° to the horizontal. It is found
Kaylis [27]

I assume the 100 N force is a pulling force directed up the incline.

The net forces on the block acting parallel and perpendicular to the incline are

∑ F[para] = 100 N - F[friction] = 0

∑ F[perp] = F[normal] - mg cos(30°) = 0

The friction in this case is the maximum static friction - the block is held at rest by static friction, and a minimum 100 N force is required to get the block to start sliding up the incline.

Then

F[friction] = 100 N

F[normal] = mg cos(30°) = (10 kg) (9.8 m/s²) cos(30°) ≈ 84.9 N

If µ is the coefficient of static friction, then

F[friction] = µ F[normal]

⇒   µ = (100 N) / (84.9 N) ≈ 1.2

5 0
2 years ago
How much power is needed to lift the 200-N object to a height of 4 m in 4 s?
Vitek1552 [10]

Answer: 2000 watts

Explanation:

Given that,

power = ?

Weight of object = 200-N

height = 4 m

Time = 4 s

Power is the rate of work done per unit time i.e Power is simply obtained by dividing work by time. Its unit is watts.

i.e Power = work / time

(since work = force x distance, and weight is the force acting on the object due to gravity)

Then, Power = (weight x distance) / time

Power = (200N x 4m) / 4s

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Power = 2000 watts

Thus, 2000 watts of power is needed to lift the object.

3 0
3 years ago
When air resistance equals the weight of an object, the object has reached
MissTica

Answer:

When air resistance equals the weight of an object, the object has reached free fall.

Explanation:

  • When an object has only force acting on it as gravity then, it experiences free fall.
  • During free fall all the forces except gravity is balanced by one another.
  • In the question, object's weight is balanced by air resistance so it is in the state of free fall.
  • At the null point of free fall, object experiences weightlessness i.e. it feels like object is not attracted by any force.  
6 0
3 years ago
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