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artcher [175]
3 years ago
12

Determine the gram formula mass of the product

Chemistry
1 answer:
dimulka [17.4K]3 years ago
6 0

For the whole set of problems, always remember the Avogadro’s number is 6.023*10^23 units per mole of a substance. Units could be atoms, molecules or formula units.

 

The first question asks for the number of molecules of NaNO3. The molar mass of NaNO3 is 85 grams per mole. So,

<span>150g NaNO3(1mole NaNO3/85 grams NaNO3)(6.023*10^23 molecules/1mole NaNO3)=1.063*10^24 molecules of NaNO3</span>

 

<span>5.7*10^46 molecules of NaNO3(1mole NaNO3/6.023*10^23 molecules)(85 grams NaNO3/1mole NaNO3) = 8.044*10^24 grams NaNO3</span>

 

For the molar mass of water, we have 18.02grams per mole.

301 moles H2O(18.02 grams H2O/1 mole H2O) = 5424.02 grams H2O

 

For the molar mass of sulfuric acid, we have 98.08 grams per mole.

 25g H2SO4(I mole H2SO4/98.08g H2SO4) = 0.2549 mole H2SO4

 

For the molar mass of Ca(OH)2, we have 74.1 grams per mole.

252gCa(OH)2(1mol/74.1g)(6.023*10^23/1mol) = 2.048*10^24 molecules of Ca(OH)2

 

For the molar mass of calcium, we have 40 grams of Ca per mole.

6.7*10^35 atoms Ca(1 mole Ca/6.023*10^23 atoms)(40g Ca/1mol Ca) = <span>4.45*10^13 grams Ca</span>

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Rate = 3.37x10-3 M^-1 min-1 [A]^2 and the initial concentration of a is 0.122M.

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3 0
2 years ago
For the reaction: N2O5(g) \longrightarrow&amp;longrightarrow; 2NO2(g) + 1/2O2(g)
ivanzaharov [21]
The given equation from the problem above is already balance,
                                 N2O5 ---> 2NO2 + 0.5O2
Since, in every mole of N2O5 consumed, 2 moles of NO2 are formed, we can answer the problem by multiplying the given rate, 7.81 mol/L.s with the ratio.
                    (7.81 mol/L.s) x (2 moles NO2 formed/ 1 mole of N2O5 consumed)
                       = 15.62 mol/L.s
The answer is the rate of formation of NO2 is approximately 15.62 mol/L.s. 
5 0
3 years ago
Explain the difference between cocl2 6h2o and anhydrous cobalt chloride
lana66690 [7]
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4 years ago
Calculate the quantity of energy released when 783 g of steam condenses.<br><br> (show work)
Angelina_Jolie [31]

Answer:

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Explanation:

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7 0
2 years ago
What is the molality of chloride ions in an aqueous solution of magnesium chloride for which xmgcl2 is 0.01?
AfilCa [17]
MgCl₂ ---> Mg(2+) + 2Cl(-)
0,01-x.............x.............2x

MgCl₂ ---> Mg(2+) + 2Cl(-)
0,01-x.............x.............2x
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The molality of chloride ions is 0,02M.
8 0
4 years ago
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