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3 years ago

A bullet is at rest. It travels a distance of 0.34m in a time of 0.0095 seconds. Calculate its acceleration.

Physics

1 answer:

tamaranim1 [39]3 years ago

7 0

Answer:

7.5 × 10^3 m/s^2

Explanation:

use the formula that does not have v in it to solve for acceleration.

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A 75-g mass sits 75 cm from the center of a rotating platform undergoing a uniform angular acceleration of 0.125 rad/s^2. The co

jasenka [17]

Answer:

velocity of mass when it slides of will be 1.36 m/sec

So option (b) will be correct option.

Explanation:

We have given mass of the slits m = 75 gram = 0.075 kg

Radius r = 75 cm = 0.75 m

Coefficient of kinetic friction $\mu =0.250$

Acceleration due to gravity $g=9.8m/sec^2$

When the mass slides of

$\frac{mv^2}{r}=\mu mg$

$v=\sqrt{\mu rg}=\sqrt{0.250\times 0.75\times 9.8}=1.36m/sec$

So velocity of mass when it slides of will be 1.36 m/sec

So option (b) will be correct option.

3 0

3 years ago

A car has a unibody-type frame and is supported by four suspension springs, each with a force constant of 29600 n/m. the combine

Dafna1 [17]

I’m done with my homework e ee was a good night I got to go to

4 0

3 years ago

A well lagged copper calorimeter of mas 120g contains 70g of water and 10g ice both at 0°C . Dry steam at 100°C is passed in unt

Lina20 [59]

Answer:

7.6 g

Explanation:

"Well lagged" means insulated, so there's no heat transfer between the calorimeter and the surroundings.

The heat gained by the copper, water, and ice = the heat lost by the steam

Heat gained by the copper:

q = mCΔT

q = (120 g) (0.40 J/g/K) (40°C − 0°C)

q = 1920 J

Heat gained by the water:

q = mCΔT

q = (70 g) (4.2 J/g/K) (40°C − 0°C)

q = 11760 J

Heat gained by the ice:

q = mL + mCΔT

q = (10 g) (320 J/g) + (10 g) (4.2 J/g/K) (40°C − 0°C)

q = 4880 J

Heat lost by the steam:

q = mL + mCΔT

q = m (2200 J/g) + m (4.2 J/g/K) (100°C − 40°C)

q = 2452 J/g m

Plugging the values into the equation:

1920 J + 11760 J + 4880 J = 2452 J/g m

18560 J = 2452 J/g m

m = 7.6 g

7 0

3 years ago

The principle of work states that the ratio of work output to work input is always

snow_lady [41]

Answer:

work output is always less than work input - the ratio is less than 1.

Explanation:

This principle comes from the fact that a machine or system cannot produce more work than is supplied to it, because this would violate the energy conservation law (work is a type of mechanical energy).

In theoretical machines called "ideal machines" the input work is the same as the output work, but these machines are only theoretical because in real applications there is always some type of energy loss, either in heat produced by a machine or processes for its operation, for this reason the output work is always less than the input work.

Regarding the ratio work output to work input:

$\frac{WO}{WI} < 1$

because work input WI is always greater than work output WO.

7 0

3 years ago

The two types of glaciers are the U type which is found in the Rocky Mountains, and the L type which can be found in Switzerland

Arturiano [62]

THE ANSWER IS TRUE
Have a nice day

4 0

3 years ago