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a phenomenon whereby the moon appears bluish owing to smoke or dust particles in the atmosphere
Answer:
no se porque xD jajjakajajjajajajjaj
Answer:
Frequency of the light will be equal to ![6.97\times 10^{1}Hz](https://tex.z-dn.net/?f=6.97%5Ctimes%2010%5E%7B1%7DHz)
Explanation:
We have given wavelength of the light ![\lambda =430nm=430\times 10^{-9}m](https://tex.z-dn.net/?f=%5Clambda%20%3D430nm%3D430%5Ctimes%2010%5E%7B-9%7Dm)
Velocity of light is equal to ![v=3\times 10^8m/sec](https://tex.z-dn.net/?f=v%3D3%5Ctimes%2010%5E8m%2Fsec)
We have to find the frequency of light
We know that velocity is equal to
, here
is wavelength and f is frequency of light
So frequency of light will be equal to ![f=\frac{v}{\lambda }=\frac{3\times 10^8}{430\times 10^{-9}}=6.97\times 10^{1}Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7Bv%7D%7B%5Clambda%20%7D%3D%5Cfrac%7B3%5Ctimes%2010%5E8%7D%7B430%5Ctimes%2010%5E%7B-9%7D%7D%3D6.97%5Ctimes%2010%5E%7B1%7DHz)
So frequency of the light will be equal to ![6.97\times 10^{1}Hz](https://tex.z-dn.net/?f=6.97%5Ctimes%2010%5E%7B1%7DHz)
Answer:
-100N
Explanation:
Newton's third law of motion states that to every force exerted on one body, there is an equal and opposite force. This means that if object A exerts an ACTION force on B, there is a force called REACTION FORCE, which is equal and opposite, exerted on A by B.
The action and reaction forces are equal in size/magnitude but opposite in direction. In this case where a tennis racket strikes a tennis ball with a force (action force) of 100N, the ball will strike the racket with a reaction force of -100N.
F(RB) = -F(BR)
Answer:
a = 1.152s
b = 0.817 m
c = 7.29m/s
Explanation: let the following
From the first equation of linear motion
V = u+at..........1
parameters be represented as :
t = Time taken
v = Final velocity
a = Acceleration due to gravity = 9.8m/s²
u = Initial velocity = 4 m/s
s = Displacement
V = 0
Substitute the values into equation 1
0 = 4-9.8(t)
-4 = -9.8t
t = 4/9.8
t = 0.408s
From : s = ut+1/2at^2.........2
S = 4×0.408+0.5(-9.8)×0.408^2
S= 1.632-4.9(0.166)
S = 1.632-0.815
S = 0.817m
Her highest height above the board is 0.817 m
Total height she would fall is 0.817+1.90 = 2.717 m
From equation 2
s = ut+1/2at^2
2.717 m = 0t+0.5(9.8)t^2
2.717 m = 0+4.9t^2
2.717 m = 4.9t^2
2.717/4.9 = t^2
0.554 =t^2
t =√0.554
t = 0.744s
Hence, her feet were in the air for 0.744+0.408seconds
= 1.152s
Also recall from equation 1
V= u+at
V = 0+9.8(0.744)
V = 7.29m/s
Hence, the velocity when she hits the water is 7.29m/s
Finally,
a = 1.152s
b = 0.817 m
c = 7.29m/s