Question

An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 32.3 m/s 32.3 m/s . It then flies a further distance of 41300 m 41300 m , and afterwards, its velocity is 43.1 m/s 43.1 m/s . Find the airplane's acceleration.

Answer 1

Answer:

$0.00986m/s^2$

Explanation:

I think there are some repetitions in the question which may be due to typographical errors. The correct question should have been as stated below:

An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 32.3 m/s . It then flies a further distance of 41300 m, and afterwards, its velocity is 43.1 m/s . Find the airplane's acceleration.

This problem could be solved using the third equation of  a uniformly accelerated motion, since the airplane is said to accelerate at a constant (uniform) rate. The equation is given by;

$v^2=u^2+2as$

where v is the final velocity, u the initial velocity, a acceleration and s distance.

$u=32.3m/s\\ v=43.1m/s\\s=41300m\\a=?$

We substitute these values into the equation and then solve for the unknown;

$43.1^2=32.3^2+2(a)(41300)\\43.1^2-32.3^2= 82600a\\1857.61-1043.29=82600a\\814.32=82600a\\Hence\\a=814.32/82600=0.00986m/s^2$