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Viktor [21]
1 year ago
11

An atom has a mass of 24 and a nuclear charge of 12. Which statement about the atom is accurate?

Physics
1 answer:
Oksana_A [137]1 year ago
5 0

The correct answer is It has equal numbers of neutrons and protons.

A characteristic that can be physically determined, the atomic mass of an atom is equal to the total mass of the protons, neutrons, and electrons that make up the atom. The number of protons in the atom's nucleus is indicated by the atomic number. It is equal to the atomic number in value. Moving over the periodic table causes the nuclear charge to grow. The charge is filled when the electrons approach the protons.

The protons and neutrons of an atom are added to determine the mass number. Therefore, the mass number for each atom will be twice the atomic number (number of protons) if the number of protons (atomic number) and neutrons are identical.

To learn more about  protons and neutrons refer the link:

brainly.com/question/13119648

#SPJ9

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Two balls are dropped from rest and allowed to fall. If one ball is allowed to fall for 1 s and the other for 3 s compare the di
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The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.

The given parameters;

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The distance traveled by each ball is calculated using the second equation of motion as shown below.

The distance traveled by the first ball is calculated as follows;

h = u_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 1^2)\\\\h = 4.9 \ m

The distance traveled by the second ball is calculated as follows;

h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 3^2)\\\\h = 44.1\ m

Thus, the second ball traveled a greater distance because it spent more time in motion.

Learn more here:brainly.com/question/5868480

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An automobile starter motor has an equivalent resistance of 0.0500Ω and is supplied by a 12.0-V battery with a 0.0100-Ω internal
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Answer

given,

resistance = 0.05 Ω

internal resistance of battery = 0.01 Ω

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a) ohm's law

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     and volage

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now,

   IR = \epsilon - Ir

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inserting the values

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