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olganol [36]
3 years ago
7

What does the electron sea model for metals suggest?

Chemistry
1 answer:
fgiga [73]3 years ago
8 0

Answer:

electron sea model for metals suggest that valence electrons drift freely around the metal cations.

Explanation:

Explanation: In electron sea model, the valence electrons in metals are delocalized instead of orbiting around the nucleus. ... These electrons are free to move within the metal atoms. Thus, we can conclude that the electron sea model for metals suggest that valence electrons drift freely around the metal cations.

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List 10 uses of metals​
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1.In electronics

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6.In agriculture

7.In the kitchen

8.Furniture

9. Security system

10 Bullion market

7 0
2 years ago
Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici
IRISSAK [1]
2CH3OH+302  -->  2C02+4H2O
4 0
3 years ago
Read 2 more answers
Foxplain the term hybridizatim​
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Answer:

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Image result for explain the term hybridization​

In chemistry, orbital hybridisation (or hybridization) is the concept of mixing atomic orbitals into new hybrid orbitals (with different energies, shapes, etc., than the component atomic orbitals) suitable for the pairing of electrons to form chemical bonds in valence bond theory.

Explanation:

6 0
3 years ago
What elements are found in salt?
devlian [24]
Sodium is a member of the alkali metal family with potassium (K) and Lithium (LI) sodium's big claim to fame is that it's one or two elements in your table salt. when bonded to chlorine (CI) THE two elements make sodium chloride
8 0
3 years ago
A 0.580 g sample of a compound containing only carbon and hydrogen contains 0.480 g of carbon and 0.100 g of hydrogen. At STP, 3
Sati [7]

Answer:

Molecular formula for the gas is: C₄H₁₀

Explanation:

Let's propose the Ideal Gases Law to determine the moles of gas, that contains 0.087 g

At STP → 1 atm and 273.15K

1 atm . 0.0336 L = n . 0.082 . 273.15 K

n = (1 atm . 0.0336 L) / (0.082 . 273.15 K)

n = 1.500 × 10⁻³ moles

Molar mass of gas = 0.087 g / 1.500 × 10⁻³ moles = 58 g/m

Now we propose rules of three:

If 0.580 g of gas has ____ 0.480 g of C _____ 0.100 g of C

58 g of gas (1mol) would have:

(58 g . 0.480) / 0.580 = 48 g of C  

(58 g . 0.100) / 0.580 = 10 g of H

 48 g of C / 12 g/mol = 4 mol

 10 g of H / 1g/mol = 10 moles

7 0
3 years ago
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