2.5m/s
Explanation:
Given parameters:
Initial velocity = 0m/s
Acceleration = 0.5m/s²
time of travel = 5s
Solution:
Final velocity = ?
Solution:
Acceleration can be defined as the change in velocity with time:
Acceleration = 
From the equation above, the unknown is final velocity:
Final velocity - initial velocity = Acceleration x time
since initial velocity = 0
Final velocity = 0.5 x 5 = 2.5m/s
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Acceleration brainly.com/question/3820012
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Given:
u(initial velocity)=0
a=5.54m/s^2
v(final velocity)=2 m/s
v=u +at
Where v is the final velocity.
u is the initial velocity
a is the acceleration.
t is the time
2=0+5.54t
t=2/5.54
t=0.36 sec
Answer:
Multiplied.
Explanation:
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Answer:
3984875 N/C
Explanation:
Applying,
E = kq/r².................. Equation 1
Where E = Electric field, q = charge, r = distance, k = coulomb's constant.
From the question,
Given: q = 7.10 mC = 0.0071 C, r = 4.0 m
Constant: k = 8.98×10⁹ Nm²/C²
Substitute these values into equation 1
E = 0.0071(8.98×10⁹)/4²
E = 3984875 N/C
Hence the electric field is 3984875 N/C
