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3 years ago

A student measures the mass 8cm block of brown sugar to be 12.9g. what is the density of the brown sugar.

Physics

1 answer:

antoniya [11.8K]3 years ago

8 0

Correction

A student measures the mass 8cm3 block of brown sugar to be 12.9g. what is the density of the brown sugar

Answer:

$1.6\ g/cm^{3}$

Explanation:

Density is defined as mass per unit volume of an object expressed as $\rho=\frac {m}{v}$ where $\rho$ is the density, m is the mass of sugar and v is the volume of the sugar. Considering that the volume is given as 8cm3 for sugar then we substitute this for v and mass of 12.9 g we substitute for g then the density will be

$\rho=\frac {12.9 g}{8 cm3}=1.6125\ g/cm^{3}\approx 1.6\ g/cm^{3}$

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Let the spring's displacement be x.

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We know that acceleration due to gravity, g is equal to 9.8 m/s².

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At equilibrium position:

Fnet = Felastic + Fg = 0

But, Felastic = -kx

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Fg = -Mt = -nmg

-kx -nmg = 0

Rearranging, we have;

kx = -nmg

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3 years ago

A 2.74 g coin, which has zero potential energy at the surface, is dropped into a 12.2 m well. After the coin comes to a stop in

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Answer:

B. - 0.328

Explanation

Potential Energy: This is the energy of a body due to position.

The S.I unit of potential energy is Joules (J).

It can be expressed mathematically as

Ep = mgh........................... Equation 1

Where Ep = potential energy, m = mass of the coin, h = height, g = acceleration due to gravity,

Given: m = 2.74 g = 0.00274 kg, h = 12.2 m, g = 9.8 m/s²

Substituting these values into equation 1

Ep = 0.00274×12.2×9.8

Ep = 0.328 J.

Note: Since the potential energy at the surface is zero, the potential Energy with respect to the surface = -0.328 J

The right option is B. - 0.328

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