Answer:
Explanation:
1 ) D)5,000,000
Compared to the chemical oxidation of one atom of carbon, a nuclear fission reaction using one atom of uranium can yield about 5000000____ times the energy output.
Energy in fission reaction comes from the conversion of mass into energy . This process results into creation of enormous amount of energy . But in the oxidation reaction of carbon , bonds are broken and new bonds are formed in which energy is used and released . The net energy released is difference of energy evolved minus energy used up . This difference is not much . Hence in such chemical reaction , energy released is not much .
2 ) B)The mass number is just an estimated mass measurement that is not precise.
In such calculation , the mass number used is just an estimated mass number and not the precise mass of particles involved . Hence , due to lack of precision in calculation , mass number appears to be constant . But actually there is decrease in mass in both fission and fusion reaction .
3 ) D
In fission reaction , large atomic nuclei splits into smaller nuclei to attain stability .
Hello!
The mass number in isotope notation is denoted A, the atomic number is denoted as Z, and the element is denoted as X.
In the given isotope, the mass of the isotope is 212 amu, and the atomic number is 82.
We know that the number of electrons, and protons are equal to the atomic number. Therefore, there are 82 protons. Also, to find the number of neutrons, we subtract the atomic number from the atomic mass.
212 - 82 = 130 neutrons
<u>Final answers</u>:
- Atomic Number: 82
- Mass number: 212
- Number of Protons: 82
- Number of Neutrons: 130
Answer:
9.91 mL
Explanation:
Using the combined gas law equation as follows;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (torr)
P2 = final pressure (torr)
V1 = initial volume (mL)
V2 = final volume (mL)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question;
V1 = 15.0mL
V2 = ?
P1 = 760 torr
P2 = 1252 torr
T1 = 10°C = 10 + 273 = 283K
T2 = 35°C = 35 + 273 = 308K
Using P1V1/T1 = P2V2/T2
760 × 15/283 = 1252 × V2/308
11400/283 = 1252V2/308
Cross multiply
11400 × 308 = 283 × 1252V2
3511200 = 354316V2
V2 = 3511200 ÷ 354316
V2 = 9.91 mL