A 0.400 kg bead slides on a straight frictionless wire and moves with a velocity of 3.50 cm/s to the right, as shown below. The
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Answer:
1.
2.
3.
4. α = 59.05°
5.
6. α = 59.05°
Explanation:
The position of the center of mass 1s before the collision is:
where
;
;
;
;
Replacing these values:
where
;
;
;
;
Replacing these values:
The velocity of their center of mass is:
where
;
;
;
;
Replacing these values:
where
;
;
;
;
Replacing these values:
So, the magnitude of the velocity is:
The angle of the velocity is:
Since on any collision, the velocity of the center of mass is preserved, then the velocity after the collision is the same as the previously calculated value of 16.66m/s at 59.0° due north of east