<span> Rising, warm, moist air masses cool and release precipitation as they rise and then at high altitude, cool
and sink back to the surface as dry air masses after moving north or south of the tropics.
</span>
Answer:

Explanation:
As we know that the energy stored in the capacitor is given as

here we know that

also we know that

now we have


now we know the formula of capacitance



Option C is the right answer
Answer:
From -15⁰ to 0⁰
H=mc¶
where H= heat absorbed or evolved
m=mass involved
c=specific heat capacity
¶=change in temperature
H=mc¶
Answer:
always same
Explanation:
velocity and speed are same upto some extend but velocity is vector while speed is scalar quantity