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3 years ago

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An on-farm diesel fuel tank is on a stand 5 feet above the ground. The tank is vented to the atmosphere (the air in the tank is

at atmospheric pressure). If the diesel level in the tank is 2.1 feet above the release point. If the density of diesel is 6.98 pounds/gallon, what is the gauge pressure of the fuel at the nozzle? What is the absolute pressure?
Gauge Pressure = XXXX psi

Absolute Pressure = XXXX psi

1 answer:

Maru [420]3 years ago

7 0

Answer:

Pg= 0.766 psi

Pabs= 15.27 psi

Explanation:

Given

h= 2.1 ft

1 ft = 0.3048 m

2.1 ft = 0.64 m

h= 0.64 m

ρ=6.98 pounds/gallon

1 pounds/gallon = 119.82 kg/m³

ρ = 825.6 kg/m³

The gauge pressure Pg

Pg= ρ g h

Pg= 825.6 x 10 x 0.64 ( take g =10 m/s²)

Pg= 5283.84 Pa

We know that

1 Pa= 0.000145 psi

Pg= 0.766 psi

Lets take atmospheric pressure Patm

Patm= 100 KPa

Pg= 5.283 KPa

Absolute pressure = Atmospheric pressure + Gauge pressure

Pabs= 100 + 5.283

Pabs= 105.283 KPa

We know that

1 KPa= 0.145 Psi

Pabs= 15.27 psi

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$H=20 cm \frac{1m}{100 cm}=0.2 m$ is the height at which the rock has the mentioned potential energy

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$W_{rock}=\frac{U}{H}$ (7)

$W_{rock}=\frac{2 Nm}{0.2 m}$ (8)

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$V_{rock}=523.59 cm^{3} \frac{1 m^{3}}{(100 cm)^{3}}=0.000523 m^{3}$ (14)

Substituting (14) in (12):

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Substituting (16) in (1):

$SG=\frac{5166.34 kg/m^{3}}{1 kg/m^{3}}$ (17)

Finally we obtain the specific gravity of the rock:

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