2 years ago

What is the total number of molecules in 34.0?

Chemistry

1 answer:

mr Goodwill [35]2 years ago

7 0

What is the element in which you are trying to find the number of molecules of?

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3 years ago

What is the volume, in milliliters, occupied by 30.07 g of an object of density equal to

den301095 [7]

Answer:

$\boxed {\tt 20.317567567568 \ mL}$

Explanation:

The density formula is:

$d=\frac{m}{v}$

Let's rearrange the formula for $v$ . the volume. Multiply both sides by $v$ , then divide by $d$ .

$d*v=\frac{m}{v}*v$

$d*v=m$

$\frac{d*v}{d}=\frac{m}{d}$

$v=\frac{m}{d}$

The volume can be found by dividing the mass by the density. The mass of the object is 30.07 grams and the density is 1.48 grams per milliliter.

$m= 30.07 \ g\\d= 1.48 \ g/mL$

$v=\frac{30.07 \ g}{1.48 \ g/mL}$

Divide. Note, when dividing, the grams, or $g$ will cancel out.

$v= \frac{30.07}{1.48 \ mL}$

$v=20.317567567568 \ mL$

The volume of the object is 20.317567567568 milliliters.

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3 years ago

Which of the following are likely to form an ionic bond

sattari [20]

Answer:

No question is posted.

But Ionic bond is mostly between metals live Na, K, Ca, Mg and strong non metals like Cl, O, F

Explanation:

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3 years ago

In a 71.4 g sample of nahco 3 3 , how many grams of sodium are present?

sweet [91]

There are 19.5 g Na in 71.4 g NaHCO₃

Calculate the <em>molecular mass of NaHCO₃</em>.

1 Na = 1 × 22.99 u = 22.99 u

1 H = 1 × 1.008 u = 1.008 u

1 C = 1 × 12.01 u = 12.01 u

3 O = 3 × 16.00 u = <u>48.00 u </u>

TOTAL = 84.008 u

So, there are 22.99 g of Na in 84.008 g NaHCO₃.

∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na

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