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Tems11 [23]
2 years ago
5

Write the empirical formula for at least four ionic compounds that could be formed from the following ions:

Chemistry
1 answer:
SpyIntel [72]2 years ago
4 0

The empirical formula of compounds formed from the given ions are as follows:

  • Pb⁴⁺ = PbO₂
  • NH₄⁺ = NH₄Cl
  • CrO₄²⁻ = Na₂CrO₄
  • SO₄²⁻ = K₂SO₄

<h3>What is the empirical formula of a compound?</h3>

The empirical formula of a compound is the simplest formula of the compound showing the simplest ratios in which elements in the compound combine.

The empirical formula of compounds formed from the given ions are as follows:

  • Pb⁴⁺ = PbO₂
  • NH₄⁺ = NH₄Cl
  • CrO₄²⁻ = Na₂CrO₄
  • SO₄²⁻ = K₂SO₄

In conclusion, the empirical formula is the simplest formula of a compound.

Learn more about empirical formula at: brainly.com/question/1581269

#SPJ1

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Which is the atomic number of an atom that forms an ion with 18 electrons and a charge of 2+?
Anettt [7]

Answer:

Calcium

Explanation:

It has 20 electrons to start, loses two to become Ca 2+, and is left with 18 electrons

5 0
3 years ago
B. from 52 moles of nitric acid, how many moles of silver nitrate will be produced?
IceJOKER [234]

Answer:

39 mol AgNO3

Explanation:

We have the equation 4HNO3 + 3Ag -----> 3AgNO3 + NO + 2H2O

We want to calculate the number of silver nitrate (AgNO3) moles that would be produced from 52 moles of nitric acid ( HNO3 )

We can calculate this by using mole ratio as well as dimensional analysis.

The mole ratio of Silver nitrate to nitric acid based on the balanced equation is 3AgNO3:4HNO3.

Using this we can create a table: The table is attached.

Breakdown of the table.

The moles of nitric acid cancel out and we multiply 52 by 3/4 to get 39 moles of Silver nitrate.

6 0
3 years ago
17 Which substance can not be broken down by a chemical change?(1) ammonia (3) propanal
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6 0
4 years ago
Read 2 more answers
Which statement describes a property that is unique to metalloids?
hodyreva [135]

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Metalloids are semiconductive.

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Use MO diagrams to place B2+, B2, and B2- in order of (a) decreasing bond energy; (b) decreasing bond length.
shepuryov [24]

We use the MO diagram for a homonuclear diatomic species (since C and N are neighbours, we treat them as the "same").

The first two electrons contribute to bonding. The next two are anti-bonding.

The next six contribute to bonding, and the following six are anti-bonding.

So, if we start with CN+, which has 4+5-1 (8) valence electrons, we note that the first two electrons contribute to bonding, while the next two cancel this out; the next four contribute to bonding, so the bond order is 4/2 = 2.

If we add one more electron to get CN, there are now 5 bonding electrons, giving bond order 5/2=2.5.

Adding one more to give CN- would give the bond order 6/2 = 3. (If we added more electrons, each one would lower the bond order.)

Given a series of molecules with identical skeletal structures, the one with the highest bond order has the highest bond energy:

CN+ < CN < CN-

Lewis structures will verify that CN- has a triple bond, but they do not work particularly well for CN+ and CN.

learn more about bond orders at

brainly.com/question/9713842

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3 0
1 year ago
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