Nitrogen and phosphorus !
2 J / 4 C = 1/2 joule per coulomb.
That's 1/2 volt.
I couldnt type it out so here's a picture
Answer:
The strength of the magnetic field is
.
Explanation:
Given that,
Length of the rod, L = 1.01 m
Speed with which the rod is moving, v = 3.47 m/s
We need to find the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an EMF of 0.265 mV across the rod. When the rod is moving with some speed, an emf gets induced and it is given by :

B is magnetic field

So, the strength of the magnetic field is
.
Answer:
a = 0.1 s b. 10 s
Explanation:
Given that,
The frequency in circular motion, f = 10 Hz
(a) Let T is the period of itsrotation. We know that,
T = 1/f
So,
T = 1/10
= 0.1 s
(b) Frequency is number of rotations per unit time. So,

Hence, this is the required solution.