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velikii [3]
4 years ago
12

What's the third pedal for in a vehicle​

Engineering
1 answer:
pshichka [43]4 years ago
6 0

Manual Transmission Cars typically have 3 pedals which are

1) Brake Pedal

2) Gas / Acceleration Pedal

3) Clutch Pedal

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Object has a mass of 0.5 kg and is 1.9 meters above the ground. What is PEg?
Ugo [173]

Answer:

Polyethylene glycol (PEG) is a biocompatible, synthetic, hydrophilic polyether compound that has many applications, mostly in the medical industry, but also in the chemical and industrial sectors.

Explanation:

6 0
2 years ago
16 engineering design process
Nesterboy [21]

Answer:

iejf go jjflkkkfffnfb ffv jedj HD video for my homework and I will be

Explanation:

for my homework and I will bemdjdjhdghy g<u>et</u><u> a</u><u> chance</u><u> to</u><u> look</u><u> at</u><u> the</u><u> </u><u>calendar</u><u> please</u><u> find</u><u> my</u><u> attached</u><u> updated</u><u>g</u><u> </u><u>my</u><u> homework</u><u> and</u><u> I</u><u> will</u><u> be</u><u> there</u><u> at</u><u> the</u><u> same</u><u> time</u><u> I</u><u> will</u><u> be</u><u> there</u><u>g</u><u> </u><u>my</u><u> homework</u><u> and</u><u> I</u><u> need</u>

6 0
3 years ago
Find the dy/dx using implicit differentiation
irina [24]

Answer:

dy/dx = (1 − 2x + 8y) / (4 + 3x − 12y)

Explanation:

d/dx (x − 4y) = d/dx (e^(2x + 3y − 1))

1 − 4 dy/dx = e^(2x + 3y − 1) (2 + 3 dy/dx)

Since x − 4y = e^(2x + 3y − 1):

1 − 4 dy/dx = (x − 4y) (2 + 3 dy/dx)

1 − 4 dy/dx = 2 (x − 4y) + 3 (x − 4y) dy/dx

1 − 4 dy/dx = 2x − 8y + (3x − 12y) dy/dx

1 − 2x + 8y = (4 + 3x − 12y) dy/dx

dy/dx = (1 − 2x + 8y) / (4 + 3x − 12y)

6 0
3 years ago
Write a statement that increases numPeople by 5. Ex: If numPeople is initially 10, the output is: There are 15 people.
BartSMP [9]

Answer:

import java.util.Scanner;

public class AssigningNumberToVariable {

public static void main (String [] args) {

int numPeople;

int numPeople_inc;

numPeople = 10;

/* solution */

numPeople_inc=numPeople+5;

System.out.print("There are ");

System.out.print(numPeople_inc);

System.out.println(" people.");

}

}

Explanation:

1. Declare a new variable called: numPeople_inc

2. Add 5 each time: numPeople_inc=numPeople+5;

3. Print the answer:  numPeople_inc=numPeople+5;

Optional, just write the line in the place where says: " your solutions goes here":

numPeople = numPeople+5;

8 0
3 years ago
The USAF is thinking of purchasing a improved automatic controller (no human required) at a cost of $100,000 that can make 4,000
blsea [12.9K]

Answer:

It would take 3225.8 hours of target detection to pay off the new controller

Explanation:

First, to find out how many hours it would take, we calculate what is the cost per contact for both options:

\mbox{cost per contact}=\frac{\mbox{cost per hour}}{\mbox{contacts per hour}} \\\\\mbox{cost per contact}_{specialist} =\frac{8 \frac{\$}{h} }{1000\frac{contacts}{hour} } =8*10^{-3} \frac{\$}{contact}\\\\\mbox{cost per contact}_{controller} =\frac{1 \frac{\$}{h} }{4000\frac{contacts}{hour} } =2.5*10^{-4} \frac{\$}{contact}

Knowing the cost per contact, we calculate savings per contact when using the controller:

Savings=\mbox{cost per contact}_{specialist}-\mbox{cost per contact}_{controller}\\Savings=8*10^{-3} \frac{\$}{contact}-2.5*10^{-4} \frac{\$}{contact}=7.75*10^{-3} \frac{\$}{contact}

Now that we know how much the automatic controller saves, we calculate how many contacts it would take to pay it off, and then, taking into account contacts per hour, how many hours:

Hours=\frac{\mbox{cost of the controller}}{\mbox{savings per contact}}*\frac{\mbox{1}}{\mbox{contacts per hour}}  \\\\Hours=\frac{\$100000}{7.75*10^{-3} \frac{\$}{contact}} *\frac{\mbox{1}}{4000\frac{contacts}{hour} }}=3225,8 \mbox{ hours}

That means, without taking into account veteran benefits (that raise the cost of the USAF specialist), it would take around 134 days of target detection to pay off the new controller.

8 0
3 years ago
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