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Naya [18.7K]
3 years ago
11

What’s a giant hunk of rock and metal

Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
5 0

Answer: “We live on a hunk of rock and metal that circles a humdrum star that is one of 400 billion other stars that make up the Milky Way Galaxy which is one of billions of other galaxies which make up a universe which may be one of a very large number, perhaps an infinite number, of other universes. That is a perspective on human life and our culture that is well worth pondering.”

― Carl Saga

Is this it mate?

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Why are gas bubbles not always a sign of a chemical change?
Mekhanik [1.2K]

Answer: its a reaction

Explanation:

like coke its a reaction between gas and oxygen

3 0
3 years ago
How many molecules are in 0.0740 mol NH3?
Mariana [72]

Number of molecules NH₃ = 4.45 x 10²²

<h3>Further explanation   </h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

This refers to the atomic total of the 12 gr C-12  which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles  

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mol of NH₃ = n = 0.074

So the number of molecules :

\tt N=n\times No\\\\N=0.0740\times 6.02\times 10^{23}\\\\N=4.45\times 10^{22}

3 0
3 years ago
In terms of entropy and energy, systems in nature tend to undergo changes toward
andrew-mc [135]
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3 years ago
How can you tell which ionic compounds will react in an aqueous solution
Darina [25.2K]
1.  Determine if the ionic substances can break apart into ions.
 - e.g. CaCO3 isn't very soluble, do it can't dissolve and dissociate.  If it can't pop apart, no ions.
2.  Swap the partners for all the other ions that you can get from step 1.  You can skip pairings with the same charge - a + can't get close to another + to react.
3.  Use solubility, acid/base, and redox rules to see if anything will happen with the ions in solution.<span />
3 0
3 years ago
Phuong trinh phan ung ohc cho +02
scZoUnD [109]

Answer:

yes

hope this helps!!!!

5 0
3 years ago
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