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Drupady [299]
3 years ago
9

What is glucose made of

Physics
1 answer:
tigry1 [53]3 years ago
3 0

Glucose is a simple sugar.

Its chemical formula is  C₆ H₁₂ O₆ .

That tells you that every glucose molecule is made of 6 atoms of carbon,
12 atoms of hydrogen, and 6 atoms of oxygen.


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A child drops a ball from a window.The ball strikes the ground in 3.0 seconds.What is the velocity of the ball the instant befor
lord [1]
It might be 4.0 or 2.22344 seconds as velocity speed
4 0
3 years ago
How are the three cell layers of an embryo related to its development?
Andru [333]
The said development of the cell where the three cell layers help out do it is called as Gastrulation. The three layers - called as ectoderm, endoderm, and mesoderm - tend to form as this happens. This is a process that's present in all living things except sponges.
7 0
3 years ago
Filiberto va a 90m/s en su carri, de repente se distrae por un par de segundos y su velocdad pasa a 40 m/s ¿cual fue su acelerac
svet-max [94.6K]

Answer:

Filiberto experimenta una deceleración de 2\,\frac{m}{s^{2}}.

Explanation:

(The problem was written in Spanish. Hence, explanation will be held in Spanish).

Asúmase que Filiberto se distrae por 2 segundos, puesto que un par equivale a dos, y que el vehículo experimenta un aceleración constante. La deceleración experimentada por el vehículo se deriva de la siguiente fórmula:

a = \frac{v-v_{o}}{\Delta t}

a = \frac{40\,\frac{m}{s}-90\,\frac{m}{s} }{2\,s}

a = -25\,\frac{m}{s^{2}}

Filiberto experimenta una deceleración de 2\,\frac{m}{s^{2}}.

7 0
3 years ago
A delta connection has a voltage of 560 V connected to it. How much voltage is dropped across each phase
SashulF [63]

Answer:

E_Phase = 560V

Explanation:

The computation of the voltage i.e. dropped across each phase is shown below:

Given that

The delta connection line voltage is

E_line = 560 V

And, in the case of delta connection, the line voltage would be equivalent to the phase voltage

That means

E_Phase = E_Line

= 560 V

Hence, the voltage i.e. dropped across each phase is

E_Phase = 560V

5 0
3 years ago
Suppose astronomers built a 20-meter telescope. How much greater would its light-collecting area be than that of the 10-meter Ke
nirvana33 [79]

Answer:

4 times greater

Explanation:

<u>Step 1:</u> Calculate light-collecting area of a  20-meter telescope (A₁) by using area of a circle.

Area of circle = π*r² =\frac{\pi d^{2}}{4}

Where d is the diameter of the circle = 20-m

A_{1} = \frac{\pi d^{2}}{4}

A_{1} = \frac{\pi (20^{2})}{4}

A₁ = 314.2 m²

<u>Step 2:</u> Calculate light-collecting area of a  10-meter Keck telescope (A₂)

A_{2} = \frac{\pi d^{2}}{4}

Where d is the diameter of the circle = 10-m

A_{2} = \frac{\pi (10^{2})}{4}

A₂ = 78.55 m²

<u>Step 3</u>: divide A₁ by A₂  

= \frac{314.2 m^2}{78.55 m^2}

= 4

Therefor,  the 20-meter telescope light-collecting area would be 4 times greater than that of the 10-meter Keck telescope.

5 0
3 years ago
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