All categories

3 years ago

A 1850 kg car moves with a velocity of 3 m/s. What is its kinetic energy? Joules

Physics

1 answer:

Schach [20]3 years ago

6 0

8325 Joules should be your correct answer.

You might be interested in

The transmission coefficient of the hypothetical disease dumas fever is 0.2. if the combined death and recovery rate is 0.4, wha

borishaifa [10]

NT = r / β
where NT is the threshold density, r is the recovery and death rate and β is the transmission coefficient.

= 0.4 / 0.2
= 2

7 0

3 years ago

For a maximum superelevation of 0.08 ft/ft and a degree of curve of 4o, calculate the maximum safe speed for the curve assuming

Mamont248 [21]

Answer:

Explanation:

Given that

Superelation= 0.08ft/ft

Given curve= u•

Curve junction factor= 0.13

DR= 5729.57795

R = 5729.57795/D

R = 5729.57795/4

R = 1432.4ft

c + f = V^2/gG

0.08 + 0.13 = V^2 / (32*1432.4)

V^2 = 9625.728 or V = 98 ft/sec

The designed speed for a project considered is a minimum value which means the highway design elements will meet or exceed the standards for the design speed. The maximum safe speed under normal condition is significantly greater than design speed

7 0

3 years ago

Volgvan

Answer:

The height is : 60.025 m

Explanation:

The flowerpot falls off the balcony with zero launch angle

Given the time of fright as 3.5 s then ;

The formula to apply is ;

$T=\sqrt{\frac{2H}{g} }\\\\3.5=\sqrt{\frac{2H}{9.8} }$

3.5²= 2H/9.8

12.25 =2H/9.8

12.25 * 9.8 = 2H

120.05 = 2H

120.05/2 = H

60.025 =H

7 0

2 years ago

The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that

pav-90 [236]

Answer:

The permittivity of rubber is $\epsilon = 8.703 *10^{-11}$

Explanation:

From the question we are told that

The magnitude of the point charge is $q_1 = 70 \ nC = 70 *10^{-9} \ C$

The diameter of the rubber shell is $d = 32 \ cm = 0.32 \ m$

The Electric field inside the rubber shell is $E = 2500 \ N/ C$

The radius of the rubber is mathematically evaluated as

$r = \frac{d}{2} = \frac{0.32}{2} = 0.16 \ m$

Generally the electric field for a point is in an insulator(rubber) is mathematically represented as

$E = \frac{Q}{ \epsilon } * \frac{1}{4 * \pi r^2}$

Where $\epsilon$ is the permittivity of rubber

=> $E * \epsilon * 4 * \pi * r^2 = Q$

=> $\epsilon = \frac{Q}{E * 4 * \pi * r^2}$

substituting values

$\epsilon = \frac{70 *10^{-9}}{2500 * 4 * 3.142 * (0.16)^2}$

$\epsilon = 8.703 *10^{-11}$

7 0

3 years ago

The diagrams show objects’ gravitational pull toward each other. Which statement describes the relationship between diagram X an

creativ13 [48]

' C ' is the only correct statement on the list. We don't know anything about diagram-x or diagram-y because we can't see them.

8 0

3 years ago

Read 2 more answers