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sveta [45]
4 years ago
8

A vehicle uses 1 7/8 gallons of gasoline to travel 56 1/4 miles. At this rate, how many miles can the vehicle travel per gallon

of gasoline.
Mathematics
1 answer:
sweet [91]4 years ago
4 0

Answer:

  30 miles

Step-by-step explanation:

In this context, "per" means "divided by", so to find miles per gallon, divide miles by gallons:

  (56 1/4 mi)/(1 7/8 gal) = 30 mi/gal

The vehicle can travel 30 miles per gallon of gas.

_____

My calculator divides mixed numbers directly, as many graphing calculators do. If you're working this out by hand, you can convert to improper fractions, then multiply the numerator by the inverse of the denominator.

  (56 1/4)/(1 7/8) = (225/4)/(15/8)

  = (225/4)·(8/15) = (225/15)·(8/4)

  = 15·2 = 30

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6 and 2/3 minus 4 and 1/2 is 13/6
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How many loads of laundry can you wash if you work 3 shifts? express your answer numerically as an integer?
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Let number of loads of laundry that you can wash in 1 shift = x

Then number of loads of laundry that you can wash in 3 shift = 3x


Numerical value of the number of loads of laundry that you can wash in 1 shift is not given so it's not possible to convert "3x" into integer.

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3 years ago
The volume of a sphere is decreasing at a constant rate of 116 cubic centimeters per second. At the instant when the volume of t
nirvana33 [79]

Answer:

\frac{dr}{dt}  = -1.325 \ cm/s

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Calculus</u>

Derivatives

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Taking Derivatives with respect to time

Step-by-step explanation:

<u>Step 1: Define</u>

Given:

<u />V = \frac{4}{3} \pi r^3<u />

<u />\frac{dV}{dt} = -116 \ cm^3/s<u />

<u />V = 77 \ cm^3<u />

<u />

<u>Step 2: Solve for </u><em><u>r</u></em>

  1. Substitute:                    77 = \frac{4}{3} \pi r^3
  2. Isolate <em>r</em> term:               \frac{77}{\frac{4}{3} \pi} = r^3
  3. Isolate <em>r</em>:                        \sqrt[3]{\frac{77}{\frac{4}{3} \pi}}  = r
  4. Evaluate:                       2.63917  = r
  5. Rewrite:                         r = 2.63917 \ cm

<u>Step 3: Differentiate</u>

<em>Differentiate the Volume Formula with respect to time t.</em>

  1. Define:                                                                                                            V = \frac{4}{3} \pi r^3
  2. Differentiate [Basic Power Rule]:                                                                   \frac{dV}{dt}  = \frac{4}{3} \pi \cdot 3 \cdot r^{3-1} \cdot \frac{dr}{dt}
  3. Simplify:                                                                                                           \frac{dV}{dt}  = 4 \pi r^2 \cdot \frac{dr}{dt}

<u>Step 4: Find radius rate</u>

  1. Substitute in variables:                    -116 \ cm^3/sec  = 4 \pi (2.63917 \ cm)^2 \cdot \frac{dr}{dt}
  2. Isolate dr/dt rate:                             \frac{-116 \ cm^3/s}{4 \pi (2.63917 \ cm)^2} = \frac{dr}{dt}
  3. Evaluate:                                          -1.3253 \ cm/s = \frac{dr}{dt}
  4. Rewrite:                                           \frac{dr}{dt}  = -1.3253 \ cm/s
  5. Round:                                             \frac{dr}{dt}  = -1.325 \ cm/s

Our radius is decreasing at a rate of -1.325 cm per second.

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Type your response in the box.
Irina18 [472]

Answer:

i need the text.

Step-by-step explanation:

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3 years ago
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