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3 years ago

M-? P=800kg /m3 V=0,5L

Physics

1 answer:

BaLLatris [955]3 years ago

5 0

Answer:400kg

Explanation:

Density=800kg/m^3

Volume=0.5L

Mass=density x volume

Mass=800 x 0.5

Mass=400kg

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A 108 kg clock initially at rest on a horizontal floor requires a 653 N horizontal force to set it in motion. After the clock is

kifflom [539]

Answer:

$\mu_s=0.61$

$\mu_k=0.49$

Explanation:

Given that,

Mass of the clock, m = 108 kg

When the clock is not moving, force acting on it, $F_1=653\ N$

For the clock in motion, force acting on it, $F_2=527\ N$

To find,

$\mu_s\ and\ \mu_k$

Solution,

When an object is at rest, the force acting on it is called force due to static friction and if the object is in motion, the force acting on its called force due to kinetic friction.

Let $\mu_s$ is the coefficient of static friction. Force is given by :

$F_s=\mu_smg$

$\mu_s=\dfrac{F_s}{mg}$

$\mu_s=\dfrac{653}{108\times 9.8}$

$\mu_s=0.61$

Let $\mu_k$ is the coefficient of kinetic friction. Force is given by :

$F_k=\mu_kmg$

$\mu_k=\dfrac{F_k}{mg}$

$\mu_k=\dfrac{527}{108\times 9.8}$

$\mu_k=0.49$

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How many elements did mendeleev place in group 2

Pepsi [2]

Answer:5

Explanation:

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3. 3.0*1015 electrons are removed from one side of a parallel plate capacitor and travel to the other side of the capacitor. You

natima [27]

Answer:

True

$Q = 480 \mu C$

Explanation:

As we know that total charge is always quantized and in the terms of multiples of charge of single electron

so we have

Q = Ne

here we know that

$N = 3.0 \times 10^{15}$

also we know that

$e = 1.6 \times 10^{-19} C$

so we have

$Q = (3.0 \times 10^{15})(1.6 \times 10^{-19} C)$

$Q = 480 \mu C$

Since this charge is in multiple of micro coulomb units so yes it is possible to measure it

and the magnitude of this charge is given as

$Q = 480\mu C$

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Plz write it in English

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