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ruslelena [56]
3 years ago
13

A man lifts a load of 20 kg Frome The ground And put it on his head 1.4m above the ground . Calculate the work done by the man.

Physics
1 answer:
Leni [432]3 years ago
5 0

Given parameters:

Mass of load = 20kg

Height of man = 1.4m

Unknown:

Work done by man = ?

Work done is the force applied to move a body in a particular direction.

Often times, it is mathematically expressed as;

           Work done  = Force x distance

In this problem, we use the formula of potential energy to find the work done;

     Work done  = Potential energy  = mgh

where m is the mass of the load

            g is the acceleration due to gravity  = 9.8m/s²

            h is the height of the body

Now, input the parameters, and solve for work done;

        Work done = 20 x 9.8 x 1.4  = 274.4J

The work done by man is  274.4J

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3 years ago
A woman walked 115 m. As she did so, her speed increased from 4.20 m/s to 5.00 m/s. How long did it take her to walk this distan
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Answer:

25 seconds

Explanation:

Assuming the woman is accelerating at a constant rate of a \;\;m/s^2 from the initial velocity, u=4.20 m/s, to the final velocity, v=5.00 m/s.

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As acceleration, a=\frac{v-u}{t}=\frac{5-4.2}{t}

\Rightarrow at=0.8\cdots(i)

Now, from the equation of motion

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\Rightarrow 115=4.2t+\frac 12 \times 0.8 t [ from equation (i)]

\Rightarrow 115=(4.2+0.4)t

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5 0
3 years ago
20 kg object travels 28 meter and stops. coefficient friction= 0.085 how much work was done by friction?
Tresset [83]
Assuming it is on a horizontal surface:
friction = μR
R = 20g (g is gravity 9.81)
so Friction = 0.085 x 20g
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7 0
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