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OlgaM077 [116]
3 years ago
13

PLEASE HURRY!!!

Physics
1 answer:
s2008m [1.1K]3 years ago
4 0

Answer:

thank you for the answer

Explanation:

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The universal force that is the weakest is gravitational. The correct answer is B. 
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A 480 g peregrine falcon reaches a speed of 69 m/s in a vertical dive called a stoop. If we assume that the falcon speeds up und
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Answer:

The minimun height is 242 [m]

Explanation:

We can solve this problem by using the principle of energy conservation, where potential energy becomes kinetic energy. We will take the point where the Falcon reaches the speed of 69 (m/s), as the point where the potential energy is zero, i.e. it will be the reference point.

At the reference point all potential energy has been transformed into kinetic energy, therefore the kinetic energy can be calculated.

E_{k}=0.5*m*v^{2} \\ where:\\v = velocity = 69 [m/s]\\m = mass = 480[g] = 0.480[kg]\\E_{k} = kinetic energy [J]\\E_{k} =0.5*0.48*(69)^{2} \\E_{k} =1142.64[J]

Now we can calculate the elevation with respect to the reference point using the definition of the potential energy.

E_{p}=m*g*h\\ E_{p}=E_{k} \\therefore\\h= E_{p}/(m*g)\\h= 1142.64/(.48*9.81)\\h=242[m]

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3 years ago
Two long, straight wires are separated by 0.12 m. The wires carry currents of 4.0 A in opposite directions, as the drawing indic
user100 [1]
If we have I= 7.5 A:

I think my solution might just help you answer the problem on your own:

You have the formulas correct, watch your signs and BRACKETS. 

B = μ0/(2π) (Current) / (Perpendicular distance) 
Since μ0=4π E -7 Tm/A, we have: 
B1 = (4πE-7 Tm/A)(7.5 A)/[2π (0.030 m)] = 5E-5 T 
B2 = (4πE-7 Tm/A)(-7.5 A)/[2π (0.150 m)] = -1E-1 T 
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(It looks like you just left out the square brackets, hence multiplying Pi and 0.03 and 0.15 instead of dividing them.) 

<span>For the point B, the two distances are -0.060 m and +0.060 m. Be careful with the signs. Unlike point A, the two components will have the same sign.</span>
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A man pulls a 50.0 kg box with a rope parallel to the ground he pulls the box 10.0 m about how much work has he done
anygoal [31]
Your answer is 5000 J

when W(work) = F X  when F= the force and X= the displacment

and F(g) = M a(g) when M= mass and a = the acceleration and in our question
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and by substitution in work equation: when x = 10 m 
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