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Burka [1]
3 years ago
7

A gas is at a pressure of 3.70 atm. What is this pressure in kilopascals?

Chemistry
1 answer:
Yanka [14]3 years ago
7 0
Answer:
                =   374.90 kPa 

Calculation:
                  As we know atm and kiloPascal are related to each other as,

                                         1 atm  =  101.325 kPa
So,
                                    3.70 atm  =   X
Solving for X,
                                     X  = (3.70 atm × 101.325 kPa) ÷ 1 atm

                                     X  =  374.90 kPa 
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Express 0.5 mg/mL in ug/uL
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3 years ago
A flask contains a gas mixture of hydrogen, nitrogen and methane. The total pressure of the mix is 3.0 atm. The partial pressure
ollegr [7]

Answer:

P_{N_2}=1.0atm

Explanation:

Hello,

Considering the Dalton's law which states that the total pressure of a gaseous system is defined by the summation of the the partial pressures of the present gases:

P_T=\Sigma P_i

For the given system:

P_T=P_{H_2}+P_{N_2}+P_{CH_4}

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3 0
3 years ago
2. The approximate concentration of hydrochloric acid, HCl, in the stomach (stomach
Sergio039 [100]

Answer:

a) 0.714g of bicarbonate of soda are required.

b) 0.221g of Al(OH)₃ are required

Explanation:

The reactions of HCl with bicarbonate of soda and aluminium hydroxide are:

HCl + NaHCO₃ → H₂O + NaCl + CO₂

3 HCl + Al(OH)₃ → 3H₂O + AlCl₃

The moles of HCl that we need neutralize are:

50mL = 0.050L * (0.17mol / L) = 0.0085 moles HCl

To solve these problem we need to find the moles of the antacid using the chemical reaction and its mass using its molar mass;

<em>a) </em><em>Moles NaHCO₃ = Moles HCl = 0.0085 moles </em>

The mass is -Molar mass NaHCO₃: -84g/mol-

0.0085 moles * (84g / mol) = 0.714g of bicarbonate of soda are required

b) 0.0085 moles HCl * (1mol Al(OH)₃ / 3mol HCl) = 2.83x10⁻³ moles Al(OH)₃

The mass is -Molar mass: 78g/mol-:

2.83x10⁻³ moles Al(OH)₃ * (78g/mol) =

<h3>0.221g of Al(OH)₃ are required</h3>
5 0
2 years ago
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