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3 years ago

What Is wrong with the name, nitrogen (V) monoxide?

Chemistry

1 answer:

tangare [24]3 years ago

8 0

Answer:

In nitrogen (V) monoxide, the V refers to an oxidation state of +5 of the nitrogen atom.

However, in nitrogen monoxide, NO, the oxidation state of the nitrogen aton is +2.

Therefore it is valid for us to say nitrogen (II) monoxide instead of nitrogen (V) monoxide.

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when 45 grams of copper (ii) carbonate are decomposed with heat how many grams of carbon dioxide will be produced

Maksim231197 [3]

Answer:

16.02 g

Explanation:

the balanced equation for the decomposition of CuCO₃ is as follows

CuCO₃ --> CuO + CO₂

molar ratio of CuCO₃ to CO₂ is 1:1

number of CuCO₃ moles decomposed - 45 g / 123.5 g/mol = 0.364 mol

according to the molar ratio

1 mol of CuCO₃ decomposes to form 1 mol of CO₂

therefore 0.364 mol of CuCO₃ decomposes to form 0.364 mol of CO₂

number of CO₂ moles produced - 0.364 mol

therefore mass of CO₂ produced - 0.364 mol x 44 g/mol = 16.02 g

16.02 g of CO₂ produced

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3 years ago

What is the de Broglie wavelength (in meters) of a 45-g golf ball traveling at 72 m/s?

Cerrena [4.2K]

Answer: The de broglie wavelength is $2.037 \times 10^{-34} m$ .

Explanation:

Calculate $\lambda = \frac{h}{p}$ as follows.

$\lambda = \frac{h}{p}$

where,

h = plank's constant = $6.6 \times 10^{-34} m^{2} kg/s$

p = momentum = $mass \times velocity$

Putting the values in the formula as follows.

$\lambda = \frac{h}{mass \times velocity}$

= $\frac {6.6 \times 10^{-34} m^{2} kg/s}{0.045 kg \times 72 m/s}$

= $2.037 \times 10^{-34} m$

Thus, the de broglie wavelength is $2.037 \times 10^{-34} m$ .

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3 years ago

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Please help-<br> thank you-

Flauer [41]

Dang that’s crazy.. Goodluck ..

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3 years ago

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2 years ago

What Is wrong with the name, nitrogen (V) monoxide?​

What Is wrong with the name, nitrogen (V) monoxide?