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I am Lyosha [343]
4 years ago
8

Write the point-slope form of the line passing through (2, -12) and perpendicular to y = 3x.

Mathematics
1 answer:
diamong [38]4 years ago
6 0

Answer:

y + 12 = - \frac{1}{3}(x - 2)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y = 3x is in the form y = mx with slope m = 3

Given the slope of a line m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{3}

Hence

y - (- 12) = - \frac{1}{3}(x - 2), that is

y + 12 = - \frac{1}{3}(x - 2) ← in point- slope form

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