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Arturiano [62]
3 years ago
5

A sailboat is traveling to the right when a gust of wind causes the boat to accelerate leftward at 2.5​​​​m​​/s2 for 4s. After t

he wind stops, the sailboat is traveling to the left with a velocity of 3.0​m/s.
Assuming the acceleration from the wind is constant, what was the initial velocity of the sailboat before the gust of wind?
Answer using a coordinate system where rightward is positive.
Physics
2 answers:
Rus_ich [418]3 years ago
4 0

Explanation :

Let rightward direction is considered as positive and leftward direction is considered as negative.

Given that,

Acceleration of the boat, a=-2.5\ m/s^2 ( in left )

Time taken, t=4\ s

Final velocity of the boat, v=-3\ m/s

We have to find initial velocity (u) of the sailboat.

Using first equation of motion :

v=u+at

u=v-at

u=-3-(-2.5)\times 4

u=-13\ m/s

So, initially the boat is moving with a speed of 13 m/s in leftwards direction.

Hence, this is the required solution.

Pavlova-9 [17]3 years ago
3 0
Taking right movement to be positive means leftward movement is negative.
Hence we have a deceleration of
a = - 2.5 {ms}^{ - 2}

t = 4s
v = 3.0 {ms}^{ - 1}
Using this 'suvat' equation
v = u + at
we can determine the initial velocity

3.0= u + -2.5(4)

3.0+2.5(4)=u

13.0 = u

Hence the initial velocity is 13.0 meters per seconds
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A proton orbits a long charged wire, making 1.80 ×106 revolutions per second. The radius of the orbit is 1.20 cm What is the wir
Fantom [35]

Answer:

linear charge density = -9.495 × 10^{-34} C/m

Explanation:

given data

revolutions per second = 1.80 × 10^{6}

radius = 1.20 cm

solution

we know that when proton to revolve around charge wire then centripetal force is require to be in orbit of radius around provide by electric force

so

- q × E = m × w² × r     ..................1

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and w = \frac{2*\pi}{T}  

w = \frac{d\theta }{dt}

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so here from equation 2

- 9 × 10^{9}  × \frac{2*linear\ charge\ density}{0.012} 1.80 × 10^{6} =  1.672 × 10^{-27} × 11304000² × 0.0120  

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8 0
3 years ago
A crate is placed on an adjustable, incline board. the coefficient of static friction between the crate and the board is 0.29.
sasho [114]

Let the angle be Θ (theta)

Let the mass of the crate be m.

a) When the crate just begins to slip. At that moment the net force will be equal to zero and the static friction will be at the maximum vale.

Normal force (N) = mg CosΘ

μ (coefficient of static friction) = 0.29

Static friction = μN = μmg CosΘ

Now, along the ramp, the equation of net force will be:

mg SinΘ - μmg CosΘ = 0

mg SinΘ = μmg CosΘ

tan Θ = μ

tan Θ = 0.29

Θ = 16.17°

b) Let the acceleration be a.

Coefficient of kinetic friction = μ = 0.26

Now, the equation of net force will be:

mg sinΘ - μ mg CosΘ = ma

a = g SinΘ - μg CosΘ

Plugging the values

a = 9.8 × 0.278 - 0.26 × 9.8 × 0.96

a = 2.7244 - 2.44608

a = 0.278 m/s^2

Hence, the acceleration is 0.278 m/s^2

7 0
3 years ago
Explain a lever and a pivot in a full sentence​
worty [1.4K]

Answer:

The lever is a movable bar that pivots on a fulcrum attached to a fixed point. The lever operates by applying forces at different distances from the fulcrum, or a pivot. As the lever rotates around the fulcrum, points farther from this pivot move faster than points closer to the pivot.

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Read 2 more answers
What velocity does a 2kg mass have when its kinetic energy is 16 J
alexandr402 [8]
We can use the equation for kinetic energy, K=1/2mv².
Your given variables are already in the correct units, so we can just plug in the variables and solve for v. 

K = 1/2mv²
16 = 1/2(2)v²
16 = (1)v²
√16 = v
v = 4 m/s

Therefore, the velocity of a 2 kg mass with 16 J of kinetic energy is 4 m/s.
Hope this is helpful!
7 0
3 years ago
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