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Arturiano [62]
3 years ago
5

A sailboat is traveling to the right when a gust of wind causes the boat to accelerate leftward at 2.5​​​​m​​/s2 for 4s. After t

he wind stops, the sailboat is traveling to the left with a velocity of 3.0​m/s.
Assuming the acceleration from the wind is constant, what was the initial velocity of the sailboat before the gust of wind?
Answer using a coordinate system where rightward is positive.
Physics
2 answers:
Rus_ich [418]3 years ago
4 0

Explanation :

Let rightward direction is considered as positive and leftward direction is considered as negative.

Given that,

Acceleration of the boat, a=-2.5\ m/s^2 ( in left )

Time taken, t=4\ s

Final velocity of the boat, v=-3\ m/s

We have to find initial velocity (u) of the sailboat.

Using first equation of motion :

v=u+at

u=v-at

u=-3-(-2.5)\times 4

u=-13\ m/s

So, initially the boat is moving with a speed of 13 m/s in leftwards direction.

Hence, this is the required solution.

Pavlova-9 [17]3 years ago
3 0
Taking right movement to be positive means leftward movement is negative.
Hence we have a deceleration of
a = - 2.5 {ms}^{ - 2}

t = 4s
v = 3.0 {ms}^{ - 1}
Using this 'suvat' equation
v = u + at
we can determine the initial velocity

3.0= u + -2.5(4)

3.0+2.5(4)=u

13.0 = u

Hence the initial velocity is 13.0 meters per seconds
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WARRIOR [948]

Answer:

ANS : .Energy spent on spraying =4.3542*10^{-4}J

Explanation:

<em>Given:</em>

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Thus, volume is conserved.

i.e ,

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Where ,

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Initial energy E_{i} = T*A_{i}\\= 0.0035 * 4 *\pi *0.01^{2}\\=4.398*10^{-6}J

Final energy E_{f}=10^{6}*T*A_{f}\\=10^{6}*0.0035*4*\pi *(0.0001)^2\\=4.39823*10^{-4}

∴  .Energy spent on spraying = =E_{f}-E{i}\\=(439.823-4.39823)*10^{-6}\\=4.3542*10^{-4}J

ANS : .Energy spent on spraying =4.3542*10^{-4}J

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3 years ago
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