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Nadusha1986 [10]
3 years ago
11

If you were choosing between two strain gauges, one which has a single resistor in a bridge that varies and one that has two res

istors that vary, one that increases and one which decreases, which would you expect to give a more linear voltage output (that is, a linear function of ‘x’, the position of the potentiometer)?

Engineering
1 answer:
Hunter-Best [27]3 years ago
4 0

Answer:

A strain gauge in which only one resistor varies is typically called a quarter bridge arrangement. The one in which 2 resistors vary, is called a half bridge arrangement, where the resistors showing opposite effects are mounted on either side of the flexing body. The figures and relationship between the output voltages and the change in resistance delta_R, is shown in the below diagram:

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In the last 5 meters of braking, you lose ___ of your speed.
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Answer:

answer is

a)

3/4

Explanation:

In the last 5 meters of braking, you lose 3/4 of your speed.

5 0
3 years ago
Electric heater wires are installed in a solid wall having a thickness of 8 cm and k=2.5 W/m.°C. The right face is exposed to an
Svet_ta [14]

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2.46 * 10⁵ W/m³

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See attached pictures for detailed explanation.

6 0
3 years ago
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How can I solve 23.5 million Nona meters to millimeters using no calculator because I have to show my work
lozanna [386]

Answer:

its so simple. u must mind some formulas.

Explanation:

mili->10^(-3)

micro->10^(-6)

nano->10^(-9)

so write the exact number and move "." to left or right depend question.

in this one:

23.5 is 23500000.0 nano with a default dot at the end

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6 0
3 years ago
In a Rankine cycle, superheated steam that enters the turbine at 1273.15 K and 1.8 MPa is then expanded to a vapor at 0.1 MPa. W
GrogVix [38]

Answer:

The shaft work generated per kilogram is -1.3 \frac{MJ}{kg}

Explanation:

Given:

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Initial Pressure P_{1} = 1.8 MPa

Final pressure P_{2} = 0.1 MPa

From the table superheated,

h_{i} = 4635 \frac{K J}{Kg} and  h_{f} = 2706.54 \frac{K J}{Kg}

Work done by shaft is,

 W = h_{f} - h_{i}

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 W = -1928.46 \frac{kJ}{kg}

But here efficiency is 0.56,

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Work = 0.56 \times(- 1928.46)

Work = -1.3 \frac{MJ}{kg}

Therefore, the shaft work generated per kilogram is -1.3 \frac{MJ}{kg}

6 0
3 years ago
Design a filter that has infinite DC gain, a gain of one from 1Hz to 100 Hz and filters (1storder) any signals above 100 Hz.a) S
EastWind [94]

Answer:

Attached below are the  sketches

answer :

c) G(s) = 100 / ( s + 100 )

d) y'(t)  + 100Y(s) = 100 X(s)

e) g(t) = e^-100t  u(t)

Explanation:

a) Sketch the bode plot

The filter here is a low pass filter

b) Sketch the s-plane

attached below.     pole ( s ) is at 100

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d) write the differential equation

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= sY(s) + 100Y = 100 X(s)

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e) write out the unforced transient response

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f) write out the frequency response

attached below

4 0
3 years ago
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