Answer:
answer is
a)
3/4
Explanation:
In the last 5 meters of braking, you lose 3/4 of your speed.
Answer:
2.46 * 10⁵ W/m³
Explanation:
See attached pictures for detailed explanation.
Answer:
its so simple. u must mind some formulas.
Explanation:
mili->10^(-3)
micro->10^(-6)
nano->10^(-9)
so write the exact number and move "." to left or right depend question.
in this one:
23.5 is 23500000.0 nano with a default dot at the end
for turning to mili u must move the dot 6 steps to left so it will be: 23.5 milimeter.
Answer:
The shaft work generated per kilogram is 
Explanation:
Given:
Temperature
K
Initial Pressure
MPa
Final pressure
MPa
From the table superheated,
and

Work done by shaft is,



But here efficiency is 0.56,
So work generated per kg is,
Work = 
Work =

Therefore, the shaft work generated per kilogram is 
Answer:
Attached below are the sketches
answer :
c) G(s) = 100 / ( s + 100 )
d) y'(t) + 100Y(s) = 100 X(s)
e) g(t) = e^-100t u(t)
Explanation:
a) Sketch the bode plot
The filter here is a low pass filter
b) Sketch the s-plane
attached below. pole ( s ) is at 100
c) write the transfer function of the filter
Transfer function ; G(s) = 100 / ( s + 100 )
d) write the differential equation
Y(s) / X(s) = 100 / s + 100
Y(s) [ s + 100 ] = 100 X(s)
= sY(s) + 100Y = 100 X(s)
∴ differential equation = y'(t) + 100Y(s) = 100 X(s)
e) write out the unforced transient response
g(t) = e^-100t u(t)
f) write out the frequency response
attached below