Answer:
The heat transfer q = 18.32W
Explanation:
In this question, we are asked to calculate the heat entering the tube and also evaluate properties at T =400K
Please check attachment for complete solution and step by step explanation
Open system because there is mass (water) flowing through the system of interest (radiator)
Answer:
0.0406 m/s
Explanation:
Given:
Diameter of the tube, D = 25 mm = 0.025 m
cross-sectional area of the tube = (π/4)D² = (π/4)(0.025)² = 4.9 × 10⁻⁴ m²
Mass flow rate = 0.01 kg/s
Now,
the mass flow rate is given as:
mass flow rate = ρAV
where,
ρ is the density of the water = 1000 kg/m³
A is the area of cross-section of the pipe
V is the average velocity through the pipe
thus,
0.01 = 1000 × 4.9 × 10⁻⁴ × V
or
V = 0.0203 m/s
also,
Reynold's number, Re = 
where,
ν is the kinematic viscosity of the water = 0.833 × 10⁻⁶ m²/s
thus,
Re = 
or
Re = 611.39 < 2000
thus,
the flow is laminar
hence,
the maximum velocity = 2 × average velocity = 2 × 0.0203 m/s
or
maximum velocity = 0.0406 m/s
<u>Answer:</u>
<u>of 150 pounds per square inch</u>
Explanation:
Note that the unit for measuring water pressure is called <u> pounds per square inch (psi)</u>
In the case of sprinklers and standpipe systems, a pressure <u>of 150 pounds per square inch</u> was used initially.