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Sladkaya [172]
2 years ago
12

Maintain a distance of at least

Engineering
2 answers:
Virty [35]2 years ago
8 0
The answer is c. 4 seconds
lilavasa [31]2 years ago
8 0
I think it may be 5 seconds let me know
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Air (ideal gas) is contained in a cylinder/piston assembly at a pressure of 150 kPa and a temperature of 127°C. Assume that the
Stels [109]

Answer:

The process is not possible.

Explanation:

We know for ideal condition, the work done for isothermal process is

W_{ideal} = P_{1}.V_{1} ln\frac{V_{2}}{V_{1}}

and for ideal gas, we know  PV = mRT

Therefore, W_{ideal} = mRTln\frac{V_{2}}{V_{1}}

                                                  = mRTln\frac{P_{1}}{P_{2}}

                                                  =  0.287 x 400ln\frac{150}{450}

                                                  = -126.12 kJ/kg (negative sign indicates that the process is compressive, so work input to the compressor is 126.12 kJ/kg )

Now we know for adiabatic compression process

                    PV^{\gamma } = C

We know \frac{T_{2}}{T_{1}}=(\frac{P_{2}}{P_{1}})^{\frac{\gamma -1}{\gamma }}

T_{2} = 556 K

For adiabatic work done, W_{adiabatic} = \frac{P_{1}\times V_{1}-P_{2}\times V_{2}}{\gamma -1}

                                                                       = \frac{mR(T_{1}-T_{2})}{\gamma -1}

                                                                       = \frac{0.287(400-556)}{1.45 -1}

                                                                       = -99.49 kJ/kg (negative sign indicates that the process is compressive, so work input to the compressor is 99.49 kJ/kg )

We know that in isothermal process, work input to the compressor is minimum. But in the above adiabatic polytropic process, work input to the compressor is less than the work done in the isothermal process.

Thus the process is not possible.

                                                             

7 0
3 years ago
Which cod is the best whoever has the best awnser gets brainliest​
Gnesinka [82]

Explanation:

black ops 2

5 0
2 years ago
Atmospheric pressure is measured to be 14.769 psia. a. What would be the equivalent reading of a water barometer (inches of H20)
Fofino [41]

Answer:

(a) water height =408.66 in.

(b) mercury height=30.04 in.

Explanation:

Given: P=14.769 psi     ( 1 psi= 6894.76 \frac{N}{m^2} )

we know that   P=\rho\times g\timesh

where \rho =Density,g=9.81\frac{m}{s^2}

     h=height.

Given that P=14.769 psi ⇒P= 101828.6 7\dfrac{N}{m^2}

(a) P=\rho_{w}\times g\times h_{w}  

     \rho_{w}=1000\frac{Kg}{m^3}

⇒101828.67=1000\times 9.81\times h_{w}

h_{w}=10.38 m

So water barometer will read 408.66 in.            (1 m=39.37 in)

(b)  P=\rho_{hg}\times g\times h_{hg}

     \rho_{hg}=13600

So 101828.67=13600\times 9.81\times h_{hg}

h_{hg}=0.763 m

So mercury barometer will read 30.04 in.

6 0
3 years ago
The human circulatory system consists of a complex branching pipe network ranging in diameter from
Stels [109]

Answer: the average velocity decreases

Explanation:

From the provided data we have:

Vessel    avg. diameter[mm] number

Aorta                 25.0                   1

Arteries             4.0                    159

Arteioles           0.06                 1.4*10^7

Capillaries         0.012               2.9*10^9

from the information, let \hat{m} be the mass flow rate, \rho is density, n number of vessels, and A is the cross-section area for each vessel

the flow rate is constant so it is equal for all vessels,

The average velocity is related to the flow rate by:

\hat{m} = v* \rho * A * n

we clear the side where v is in:

v = \frac{\hat{m}}{\rho A n}

area is π*R^2 where R is the average radius of the vessel (diameter/2)

we get:

v = \frac{\hat{m}}{\rho \pi R^2 n}

you can directly see in the last equation that if we go from the aorta to the capillaries, the number of vessels is going to increase ( n will increase and R is going to decrease ) . From the table, R is significantly smaller in magnitude orders than n, therefore, it wont impact the results as much as n. On the other hand, n will change from 1 to 2.9 giga vessels which will dramatically reduce the average blood velocity

8 0
3 years ago
3. Technician A says passive permanent
Angelina_Jolie [31]

Answer:

Both technician A and B

Explanation:

Passive permanent  magnet ABS wheel speed sensors produce an  A/C voltage signal. Wheel speed sensors are a necessary ABS component and sensor input. It is used to inform the ABS control module of rotational wheel speed. A passive sensor creates an AC signal that changes frequency as the wheel changes speed. Moreover, input  from wheel speed sensors are used for anti- lock brake, electronic traction control, and  electronic stability control systems. Therefore, both technicians are correct.

6 0
3 years ago
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