Maintain a distance of at least
2 answers:
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Answer:
c. V2 equals V1
Explanation:
We can answer this question by using the continuity equation, which states that:
(1)
where
A1 is the cross-sectional area in the first section of the pipe
A2 is the cross-sectional area in the second section of the pipe
v1 is the velocity of the fluid in the first section of the pipe
v2 is the velocity of the fluid in the second section of the pipe
In this problem, we are told that the pipe has a uniform cross sectional area, so:
A1 = A2
As a consequence, according to eq.(1), this means that
v1 = v2
so, the velocity of the fluid in the pipe does not change.
Answer:
<em>Heat is lost at the rate of 750 J/s or W</em>
<em>The thermal resistance is 1 K/W</em>
Explanation:
interior temperature = 900 °C
wall thickness t = 60 cm = 0.6 m
width = 1 m
breadth = 1.5 m
thermal conductivity k = 0.4 W/m-K
outside temperature = 150 °C
heat through the wall = ?
The area of the wall A = w x b = 1 x 1.5 = 1.5 m^2
Temperature difference =
-
= 900 - 150 = 750 °C
note that is also equal to 750 K since to convert from °C to K we'll have to add 273 to both temperature, which will still cancel out when we subtract the two temperatures.
To get the heat that escapes through the wall, we use the equation
Q = Ak
substituting values, we have
Q = 1.5 x 0.4 x = <em>750 J/s or W</em>
Thermal resistance =
= 750/750 =<em> 1 K/W</em>