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madam [21]
2 years ago
5

An FPC 4 m2 in area is tested during the night to measure the overall heat loss coefficient. Water at 60 C circulates through th

e collector at a flow rate of 0.06 l/s. The ambient temperature is 8 C and the exit temperature is 49 C. Determine the overall heat loss coefficient.
Engineering
1 answer:
sp2606 [1]2 years ago
7 0

Answer:

<em> - 14.943 W/m^2K  ( negative sign indicates cooling ) </em>

Explanation:

Given data:

Area of FPC = 4 m^2

temp of water = 60°C

flow rate = 0.06 l/s

ambient temperature = 8°C

exit temperature = 49°C

<u>Calculate the overall heat loss coefficient </u>

Note : heat lost by water = heat loss through convection

m*Cp*dT  = h*A * ( T - To )

∴ dT / T - To = h*A / m*Cp  ( integrate the relation )

In ( \frac{49-8}{60-8} ) =  h* 4 / ( 0.06 * 10^-3 * 1000 * 4180 )

In ( 41 / 52 ) = 0.0159*h

hence h = - 0.2376 / 0.0159

              = - 14.943  W/m^2K  ( heat loss coefficient )

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Answer:

books = []

   fp = open("bookTitles.txt")

   for line in fp.readlines():

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   fp.close()

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   for title in books:

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3 years ago
Which of the following characteristics would not give animals an advantage in the ocean?
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8 0
3 years ago
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According to the amortization table, Demarco and Tanya will pay a total of in interest over the life of their loan.
Ymorist [56]

Answer:

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You divide the interest with number of payments done in a year where monthly are divided by 12.Multiplying it by loan balance in the first month which is your principal amount gives the interest rate to pay for that month.

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3 years ago
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For some transformation having kinetics that obey the Avrami equation (Equation 10.17), the parameter n is known to have a value
OleMash [197]

Answer:

t = 25.10 sec

Explanation:

we know that Avrami equation

Y = 1 - e^{-kt^n}

here Y is percentage of completion  of reaction = 50%

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so,

0.50 = 1 - e^{-k^146^2.1}

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taking natural log on both side

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t^{2.1} = 869.96

t = 25.10 sec

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3 years ago
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