1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BlackZzzverrR [31]
3 years ago
5

Two loudspeakers are about 10 m apart in the front of a large classroom. if either speaker plays a pure tone at a single frequen

cy of 400 hz, the loudness seems pretty even as you wander around the room, and gradually decreases in volume as you move farther from the speaker. if both speakers then play the same tone together, what do you hear as you wander around the room?
Physics
2 answers:
Ronch [10]3 years ago
5 0
The observed differences in amplitudes are due to interference between the sound waves. The decrease in amplitude is due to destructive interference of the waves and the increase in amplitude is due to constructive interference.
Svetradugi [14.3K]3 years ago
5 0

<em>As the person moves around the room, he will find several point where the sound is maximum and several point where there is no sound. It is due to constructive and destructive interference of sound.</em>

Explanation:

The two loudspeakers kept at a distance of 10\text{ m} from one another produce the sound. If the person moving in the room listens to the sound of only one loudspeaker at a time, the intensity of the sound will be higher when he is near the loudspeaker and it will decrease as the person will move away from it.

If both the loudspeakers are switched on, the sound waves from both the loudspeakers can be heard in the room. As the sound waves travel throughout the room, they interfere with one another.

The interference of the sound waves causes the constructive interference and destructive interference in the room. Due to this, there are points of constructive interference where the intensity of the sound is highest due to both speakers.

Whereas at the point of destructive interference, the intensity of the sound is minimum.

Thus, <em>As the person moves around the room, he will find several point where the sound is maximum and several point where there is no sound. It is due to constructive and destructive interference of sound.</em>

<em></em>

Learn More:

1. The increase in the volume of the gas brainly.com/question/9979757

2. Conservation of momentum of car during collision brainly.com/question/9484203

3. Compare the surface are to volume of the planet Earth and Venus brainly.com/question/7227193

Answer Details:

Grade: High School

Subject: Physics

Chapter: Sound

Keywords:

Two loudspeakers, large classroom, loudness, intensity, constructive, destructive, interference, wander around, move farther.

You might be interested in
Can anyone help? <br> Please and thank you
Juliette [100K]

Kinetic energy is calculated as such: KE=\frac{1}{2} mv^{2} | therefore, KE=0.913598 J

7 0
3 years ago
022 (part 1 of 4) 10.0 points A ball is thrown vertically upward with a speed of 24.5 m/s. How high does it rise? The accelerati
svetoff [14.1K]

1)

Answer:

Part 1)

H = 30.6 m

Part 2)

t = 2.5 s

Part 3)

t = 2.5 s

Part 4)

v_f = 24.5 m/s

Explanation:

Part 1)

initial speed of the ball upwards

v_i = 24.5 m/s

so maximum height of the ball is given by

H = \frac{v_i^2}{2g}

H = \frac{24.5^2}{2(9.80)}

H = 30.6 m

Part 2)

As we know that final speed will be zero at maximum height

so we will have

v_f - v_i = at

0 - 24.5 = (-9.8)t

t = 2.5 s

Part 3)

Since the time of ascent of ball is same as time of decent of the ball

so here ball will same time to hit the ground back

so here it is given as

t = 2.5 s

Part 4)

since the acceleration due to earth will be same during its return path as well as the time of the motion is also same

so here its final speed will be same as that of initial speed

so we have

v_f = 24.5 m/s

2)

Answer:

a = 9.76 m/s/s

Explanation:

As we know that the object is released from rest

so the displacement of the object in vertical direction is given as

y = \frac{1}{2}at^2

4.88 = \frac{1}{2}a(1^2)

a = 9.76 m/s^2

3)

Answer:

v = 29.7 m/s

Explanation:

acceleration of the rocket is given as

a = 90 m/s^2

time taken by the rocket

t = 0.33 min

final speed of the rocket is given as

v_f = v_i + at

v_f = 0 + (90)(0.33)

v_f = 29.7 m/s

4)

Answer:

Part 1)

y = 25.95 m

Part 2)

d = 6.72 m

Explanation:

Part 1)

As it took t = 2.3 s to hit the water surface

so here we will have

y = \frac{1}{2}gt^2

y = \frac{1}{2}(9.81)(2.3^2)

y = 25.95 m

Part 2)

Distance traveled by it in horizontal direction is given as

d = v_x t

d = 2.92 \times 2.3

d = 6.72 m

6 0
3 years ago
a flag of mass 2.5 kg is supported by a single rope. A strong horizontal wind exerts a force of 12 N on the flag. Calculate the
tatuchka [14]
The free-body diagram of the forces acting on the flag is in the picture in attachment.

We have: the weight, downward, with magnitude
W=mg = (2.5 kg)(9.81 m/s^2)=24.5 N
the force of the wind F, acting horizontally, with intensity
F=12 N
and the tension T of the rope. To write the conditions of equilibrium, we must decompose T on both x- and y-axis (x-axis is taken horizontally whil y-axis is taken vertically):
T \cos \alpha -F=0
T \sin \alpha -W=
By dividing the second equation by the first one, we get
\tan \alpha =  \frac{W}{F}= \frac{24.5 N}{12 N}=2.04
From which we find
\alpha = 63.8 ^{\circ}
which is the angle of the rope with respect to the horizontal.

By replacing this value into the first equation, we can also find the tension of the rope:
T= \frac{F}{\cos \alpha}= \frac{12 N}{\cos 63.8^{\circ}}=27.2 N




7 0
3 years ago
Identify the region in the image where lighter elements, such as hydrogen or helium, are more likely to be found in a liquid or
Annette [7]

Lower in an arrangement

3 0
3 years ago
Read 2 more answers
A proton has been accelerated from rest through a potential difference of -1000 v . part a what is the proton's kinetic energy,
wlad13 [49]
We can apply the law of conservation of energy here. The total energy of the proton must remain constant, so the sum of the variation of electric potential energy and of kinetic energy of the proton must be zero:
\Delta U + \Delta K=0
which means
\Delta K = - \Delta U
The variation of electric potential energy is equal to the product between the charge of the proton (q=1eV) and the potential difference (\Delta V=-1000 V):
\Delta U = q \Delta V=(1 eV)(-1000 V)=-1000 eV
Therefore, the kinetic energy gained by the proton is
\Delta K = -(-1000 eV)=1000 eV
<span>And since the initial kinetic energy of the proton was zero (it started from rest), then this 1000 eV corresponds to the final kinetic energy of the proton.</span>
4 0
3 years ago
Read 2 more answers
Other questions:
  • A hypothetical wi-fi transmission can take place at any of three speeds depending on the condition of the radio channel between
    8·1 answer
  • A vehicle traveling at a steady speed takes 4 hours to travel 244 km. calculate the average speed of this vehicle.
    8·1 answer
  • Which of the following terms describes the primary core of a comet?
    9·1 answer
  • (a) If the maximum acceleration that is tolerable for passengers in a subway train is 1.34 m/s² and subway stations are located
    8·1 answer
  • If the gap between C and the rigid wall at D is initially 0.15 mm, determine the magnitudes of the support reactions at A and D
    6·1 answer
  • a farmer lifts a bale of hay that is 12m off the ground . If he uses a force of 350 n, how much work does the farmer do?
    10·1 answer
  • Can someone please answer this ? it doesn’t make sense to me
    15·1 answer
  • A fluid flows through a pipe whose cross-sectional area changes from 2.00 m2 to 0.50 m2 . If the fluid’s speed in the wide part
    14·1 answer
  • What is the critical angle θcrit for light propagating from a material with index of refraction of 1.50 to a material with inde
    8·1 answer
  • Which item could you use in place of an ammeter to demonstrate that a
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!